Lm1:
2 |^ 2 = 2 * 2
by POLYEQ_5:1;
Lm2:
2 |^ 3 = (2 * 2) * 2
by POLYEQ_5:2;
Lm3:
2 |^ 4 = ((2 * 2) * 2) * 2
by POLYEQ_5:3;
Lm4:
2 |^ 5 = (((2 * 2) * 2) * 2) * 2
by NUMBER02:1;
Lm5:
2 |^ 6 = ((((2 * 2) * 2) * 2) * 2) * 2
by NUMBER02:2;
Lm6:
2 |^ 8 = ((((((2 * 2) * 2) * 2) * 2) * 2) * 2) * 2
by NUMBER02:4;
Lm7:
2 |^ 10 = ((((((((2 * 2) * 2) * 2) * 2) * 2) * 2) * 2) * 2) * 2
by NUMBER02:6;
Lm8:
2 |^ 11 = (((((((((2 * 2) * 2) * 2) * 2) * 2) * 2) * 2) * 2) * 2) * 2
by NUMBER09:1;
Lm9:
2 |^ 14 = ((((((((((((2 * 2) * 2) * 2) * 2) * 2) * 2) * 2) * 2) * 2) * 2) * 2) * 2) * 2
by NUMBER09:4;
Lm10:
2 |^ 18 = ((((((((((((((((2 * 2) * 2) * 2) * 2) * 2) * 2) * 2) * 2) * 2) * 2) * 2) * 2) * 2) * 2) * 2) * 2) * 2
by NUMBER09:8;
Lm11:
2 |^ (8 * 4) = (2 |^ 8) |^ 4
by NEWTON:9;
Lm12:
256 |^ 4 = ((256 * 256) * 256) * 256
by POLYEQ_5:3;
theorem Th2:
for
a,
b,
c,
d,
e being
object holds
dom <*a,b,c,d,e*> = {1,2,3,4,5}
theorem Th11:
for
c1,
c2,
c3,
c4,
c5 being
Complex holds
<*c1,c2,c3,c4,c5*> ^2 = <*(c1 ^2),(c2 ^2),(c3 ^2),(c4 ^2),(c5 ^2)*>
theorem Th12:
for
c1,
c2,
c3,
c4,
c5,
c6 being
Complex holds
<*c1,c2,c3,c4,c5,c6*> ^2 = <*(c1 ^2),(c2 ^2),(c3 ^2),(c4 ^2),(c5 ^2),(c6 ^2)*>
theorem Th13:
for
c1,
c2,
c3,
c4,
c5,
c6,
c7 being
Complex holds
<*c1,c2,c3,c4,c5,c6,c7*> ^2 = <*(c1 ^2),(c2 ^2),(c3 ^2),(c4 ^2),(c5 ^2),(c6 ^2),(c7 ^2)*>
theorem Th14:
for
c1,
c2,
c3,
c4,
c5,
c6,
c7,
c8 being
Complex holds
<*c1,c2,c3,c4,c5,c6,c7,c8*> ^2 = <*(c1 ^2),(c2 ^2),(c3 ^2),(c4 ^2),(c5 ^2),(c6 ^2),(c7 ^2),(c8 ^2)*>
theorem Th16:
for
c1,
c2,
c3,
c4,
c5 being
Complex holds
<*c1,c2,c3,c4,c5*> " = <*(c1 "),(c2 "),(c3 "),(c4 "),(c5 ")*>
theorem Th17:
for
c1,
c2,
c3,
c4,
c5,
c6 being
Complex holds
<*c1,c2,c3,c4,c5,c6*> " = <*(c1 "),(c2 "),(c3 "),(c4 "),(c5 "),(c6 ")*>
theorem Th18:
for
c1,
c2,
c3,
c4,
c5,
c6,
c7 being
Complex holds
<*c1,c2,c3,c4,c5,c6,c7*> " = <*(c1 "),(c2 "),(c3 "),(c4 "),(c5 "),(c6 "),(c7 ")*>
theorem Th19:
for
c1,
c2,
c3,
c4,
c5,
c6,
c7,
c8 being
Complex holds
<*c1,c2,c3,c4,c5,c6,c7,c8*> " = <*(c1 "),(c2 "),(c3 "),(c4 "),(c5 "),(c6 "),(c7 "),(c8 ")*>
theorem Th21:
for
c1,
c2,
c3,
c4,
c5 being
Complex holds
Sum <*c1,c2,c3,c4,c5*> = (((c1 + c2) + c3) + c4) + c5
theorem Th22:
for
c1,
c2,
c3,
c4,
c5,
c6 being
Complex holds
Sum <*c1,c2,c3,c4,c5,c6*> = ((((c1 + c2) + c3) + c4) + c5) + c6
theorem Th23:
for
c1,
c2,
c3,
c4,
c5,
c6,
c7 being
Complex holds
Sum <*c1,c2,c3,c4,c5,c6,c7*> = (((((c1 + c2) + c3) + c4) + c5) + c6) + c7
theorem Th24:
for
c1,
c2,
c3,
c4,
c5,
c6,
c7,
c8 being
Complex holds
Sum <*c1,c2,c3,c4,c5,c6,c7,c8*> = ((((((c1 + c2) + c3) + c4) + c5) + c6) + c7) + c8
Lm13:
for k being Integer st k <> 1 holds
not { ((2 |^ (2 |^ n)) + k) where n is positive Nat : (2 |^ (2 |^ n)) + k is composite } is empty
Lm14:
for s being positive Nat holds 2 |^ (2 |^ ((2 * s) + 1)) >= 256
Lm15:
for s being positive Nat holds 2 |^ (2 |^ ((4 * s) + 1)) >= 2 |^ 32
Lm16:
for s being positive Nat holds 2 |^ (2 |^ ((6 * s) + 2)) >= 2 |^ 256
Lm17:
for s being positive Nat holds 2 |^ (2 |^ ((10 * s) + 1)) >= 2 |^ 2048
theorem
for
x,
y being
positive Nat holds
(
((x * y) + x) + y = 2
|^ 32 iff ( (
x = 640 &
y = 6700416 ) or (
x = 6700416 &
y = 640 ) ) )
Lm19:
for f being real-valued positive FinSequence st GMean f = Mean f holds
f is constant
Lm20:
now for a, b, c, d being positive Real holds ((a * b) * c) * d <= ((((a + b) + c) + d) / 4) |^ 4
let a,
b,
c,
d be
positive Real;
((a * b) * c) * d <= ((((a + b) + c) + d) / 4) |^ 4set f =
<*a,b,c,d*>;
A1:
len <*a,b,c,d*> = 4
by FINSEQ_4:76;
A2:
Sum <*a,b,c,d*> = ((a + b) + c) + d
by RVSUM_1:142;
(GMean <*a,b,c,d*>) |^ 4
<= (Mean <*a,b,c,d*>) |^ 4
by PREPOWER:9, RVSUM_3:47;
hence
((a * b) * c) * d <= ((((a + b) + c) + d) / 4) |^ 4
by A1, A2, Th88;
verum
end;
theorem
{ [x,y,z,t] where x, y, z, t is positive Integer : (((x / y) + (y / z)) + (z / t)) + (t / x) = 4 } = { [x,y,z,t] where x, y, z, t is positive Integer : ( x = y & y = z & z = t ) }
registration
let a,
b,
c,
d be
Nat;
reduce In (
[a,b,c,d],
[:NAT,NAT,NAT,NAT:])
to [a,b,c,d];
reducibility
In ([a,b,c,d],[:NAT,NAT,NAT,NAT:]) = [a,b,c,d]
end;
registration
let a,
b,
c,
d be
positive Nat;
reduce In (
[a,b,c,d],
[:NATPLUS,NATPLUS,NATPLUS,NATPLUS:])
to [a,b,c,d];
reducibility
In ([a,b,c,d],[:NATPLUS,NATPLUS,NATPLUS,NATPLUS:]) = [a,b,c,d]
end;
definition
set A =
NATPLUS ;
set D =
[:NATPLUS,NATPLUS,NATPLUS,NATPLUS:];
existence
ex b1 being Function of NATPLUS,[:NATPLUS,NATPLUS,NATPLUS,NATPLUS:] st
for n being positive Nat holds b1 . n = [n,n,n,n]
uniqueness
for b1, b2 being Function of NATPLUS,[:NATPLUS,NATPLUS,NATPLUS,NATPLUS:] st ( for n being positive Nat holds b1 . n = [n,n,n,n] ) & ( for n being positive Nat holds b2 . n = [n,n,n,n] ) holds
b1 = b2
end;
deffunc H1( object ) -> set = <*$1*>;
Lm21:
len <*2*> = 1
by FINSEQ_1:39;
Lm22:
len <*2,3*> = 2
by FINSEQ_1:44;
Lm23:
now for s being positive Nat holds
( s = 1 or s = 2 or s = 3 or s >= 4 )
let s be
positive Nat;
( s = 1 or s = 2 or s = 3 or s >= 4 )thus
(
s = 1 or
s = 2 or
s = 3 or
s >= 4 )
verum
proof
per cases
( s <= 3 or s > 3 )
;
suppose
s <= 3
;
( s = 1 or s = 2 or s = 3 or s >= 4 )
then
not not
s = 0 & ... & not
s = 3
;
hence
(
s = 1 or
s = 2 or
s = 3 or
s >= 4 )
;
verum
end;
end;
end;
end;
Lm24:
now for s being positive Nat holds
( s = 1 or s = 2 or s = 3 or s = 4 or s >= 5 )
let s be
positive Nat;
( s = 1 or s = 2 or s = 3 or s = 4 or s >= 5 )thus
(
s = 1 or
s = 2 or
s = 3 or
s = 4 or
s >= 5 )
verum
proof
per cases
( s <= 4 or s > 4 )
;
suppose
s <= 4
;
( s = 1 or s = 2 or s = 3 or s = 4 or s >= 5 )
then
not not
s = 0 & ... & not
s = 4
;
hence
(
s = 1 or
s = 2 or
s = 3 or
s = 4 or
s >= 5 )
;
verum
end;
suppose
s > 4
;
( s = 1 or s = 2 or s = 3 or s = 4 or s >= 5 )
then
s >= 4
+ 1
by NAT_1:13;
hence
(
s = 1 or
s = 2 or
s = 3 or
s = 4 or
s >= 5 )
;
verum
end;
end;
end;
end;
Lm25:
now for s being positive Nat holds
( s = 1 or s = 2 or s = 3 or s = 4 or s = 5 or s = 6 or s >= 7 )
let s be
positive Nat;
( s = 1 or s = 2 or s = 3 or s = 4 or s = 5 or s = 6 or s >= 7 )thus
(
s = 1 or
s = 2 or
s = 3 or
s = 4 or
s = 5 or
s = 6 or
s >= 7 )
verum
proof
per cases
( s <= 6 or s > 6 )
;
suppose
s <= 6
;
( s = 1 or s = 2 or s = 3 or s = 4 or s = 5 or s = 6 or s >= 7 )
then
not not
s = 0 & ... & not
s = 6
;
hence
(
s = 1 or
s = 2 or
s = 3 or
s = 4 or
s = 5 or
s = 6 or
s >= 7 )
;
verum
end;
suppose
s > 6
;
( s = 1 or s = 2 or s = 3 or s = 4 or s = 5 or s = 6 or s >= 7 )
then
s >= 6
+ 1
by NAT_1:13;
hence
(
s = 1 or
s = 2 or
s = 3 or
s = 4 or
s = 5 or
s = 6 or
s >= 7 )
;
verum
end;
end;
end;
end;
deffunc H2( Nat) -> set = Triangle $1;
registration
let a,
b,
c,
d,
e,
f be
triangular Nat;
coherence
<*a,b,c,d,e,f*> is triangular-valued
;
end;
Lm26:
3 >= 2 + 1
;
Lm27:
now for s being positive Nat holds
( s = 1 or s = 2 or s = 3 or s = 4 or s = 5 or s >= 6 )
let s be
positive Nat;
( s = 1 or s = 2 or s = 3 or s = 4 or s = 5 or s >= 6 )thus
(
s = 1 or
s = 2 or
s = 3 or
s = 4 or
s = 5 or
s >= 6 )
verum
proof
per cases
( s <= 5 or s > 5 )
;
suppose
s <= 5
;
( s = 1 or s = 2 or s = 3 or s = 4 or s = 5 or s >= 6 )
then
not not
s = 0 & ... & not
s = 5
;
hence
(
s = 1 or
s = 2 or
s = 3 or
s = 4 or
s = 5 or
s >= 6 )
;
verum
end;
suppose
s > 5
;
( s = 1 or s = 2 or s = 3 or s = 4 or s = 5 or s >= 6 )
then
s >= 5
+ 1
by NAT_1:13;
hence
(
s = 1 or
s = 2 or
s = 3 or
s = 4 or
s = 5 or
s >= 6 )
;
verum
end;
end;
end;
end;
Lm28:
for s being positive Nat
for f being b1 -element natural-valued positive FinSequence st f is with_sum_of_squares_of_reciprocals_equal_1 holds
ex g being b1 + 3 -element natural-valued positive FinSequence st g is with_sum_of_squares_of_reciprocals_equal_1
scheme
STEP2a{
F1()
-> Nat,
P1[
Nat] } :
for
k being
Nat st
k >= F1() holds
P1[
k]
provided
A1:
P1[
F1()]
and A2:
P1[
F1()
+ 1]
and A3:
for
k being
Nat st
k >= F1() &
P1[
k] &
P1[
k + 1] holds
P1[
k + 2]
scheme
STEP2{
P1[
Nat] } :
for
k being
Nat holds
P1[
k]
provided
A1:
for
k being
Nat holds
(
P1[2
* k] &
P1[
(2 * k) + 1] )
scheme
STEP3{
P1[
Nat] } :
for
k being
Nat holds
P1[
k]
provided
A1:
for
k being
Nat holds
(
P1[3
* k] &
P1[
(3 * k) + 1] &
P1[
(3 * k) + 2] )
scheme
STEP4{
P1[
Nat] } :
for
k being
Nat holds
P1[
k]
provided
A1:
for
k being
Nat holds
(
P1[4
* k] &
P1[
(4 * k) + 1] &
P1[
(4 * k) + 2] &
P1[
(4 * k) + 3] )
Lm31:
for s being positive Nat
for f being b1 + 1 -element natural-valued positive FinSequence st f is a_solution_of_Sierp169 holds
ex g being (b1 + 2) + 1 -element natural-valued positive FinSequence st g is a_solution_of_Sierp169