Lm1:
2 |^ 2 = 2 * 2
by NEWTON:81;
Lm2:
3 |^ 2 = 3 * 3
by NEWTON:81;
Lm3:
1 mod 4 = 1
by NAT_D:24;
registration
let a,
b,
c,
d be
Integer;
reduce In (
[a,b,c,d],
[:INT,INT,INT,INT:])
to [a,b,c,d];
reducibility
In ([a,b,c,d],[:INT,INT,INT,INT:]) = [a,b,c,d]
end;
theorem Th6:
for
m,
n being
Nat holds
( not
(n * m) mod 4
= 1 or
n mod 4
= 1 or
n mod 4
= 3 )
Lm4:
for k, n being Nat st n <> 1 & n divides 2 |^ k & not n mod 4 = 0 holds
n mod 4 = 2
Lm5:
for X being finite set
for X1 being set
for p being Prime
for i being Nat st X = { k where k is Nat : k divides p |^ i } & X1 = { k where k is Nat : k divides p |^ (i + 1) } holds
( not p |^ (i + 1) in X & X \/ {(p |^ (i + 1))} = X1 )
theorem Th18:
for
p being
Prime for
m,
n being
Nat st
p mod 4
= 3 holds
(
(divisors ((p |^ n),4,1)) \/ (divisors ((p |^ n),4,3)) = { k where k is Nat : k divides p |^ n } & (
n = 2
* m implies (
card (divisors ((p |^ n),4,1)) = m + 1 &
card (divisors ((p |^ n),4,3)) = m ) ) & (
n = (2 * m) + 1 implies (
card (divisors ((p |^ n),4,1)) = m + 1 &
card (divisors ((p |^ n),4,3)) = m + 1 ) ) )
Lm6:
for n being Nat
for p being Prime holds card (divisors ((p |^ n),4,1)) >= card (divisors ((p |^ n),4,3))
Lm7:
for n being Nat ex k being Nat st 3 |^ (2 * n) = (4 * k) + 1
Lm8:
for n being Nat ex k being Nat st 3 |^ ((2 * n) + 1) = (4 * k) + 3
Lm9:
for n being non zero Nat holds { k where k is Nat : k divides n } is finite
definition
let s be
Nat;
existence
ex b1 being FinSequence of NAT st
( len b1 = s & ( for k being non zero Nat st k <= s holds
for e being Nat st e = (Product (PrimeNumbersFS s)) / (primenumber (k - 1)) holds
b1 . k = (CRT (0,e,(- 1),(primenumber (k - 1)))) + (Product (PrimeNumbersFS s)) ) )
uniqueness
for b1, b2 being FinSequence of NAT st len b1 = s & ( for k being non zero Nat st k <= s holds
for e being Nat st e = (Product (PrimeNumbersFS s)) / (primenumber (k - 1)) holds
b1 . k = (CRT (0,e,(- 1),(primenumber (k - 1)))) + (Product (PrimeNumbersFS s)) ) & len b2 = s & ( for k being non zero Nat st k <= s holds
for e being Nat st e = (Product (PrimeNumbersFS s)) / (primenumber (k - 1)) holds
b2 . k = (CRT (0,e,(- 1),(primenumber (k - 1)))) + (Product (PrimeNumbersFS s)) ) holds
b1 = b2
end;
theorem
for
x,
y,
z,
t being
positive Nat st
x <= y &
y <= z &
z <= t holds
(
(((1 / x) + (1 / y)) + (1 / z)) + (1 / t) = 1 iff ( (
x = 2 &
y = 3 &
z = 7 &
t = 42 ) or (
x = 2 &
y = 3 &
z = 8 &
t = 24 ) or (
x = 2 &
y = 3 &
z = 9 &
t = 18 ) or (
x = 2 &
y = 3 &
z = 10 &
t = 15 ) or (
x = 2 &
y = 3 &
z = 12 &
t = 12 ) or (
x = 2 &
y = 4 &
z = 5 &
t = 20 ) or (
x = 2 &
y = 4 &
z = 6 &
t = 12 ) or (
x = 2 &
y = 4 &
z = 8 &
t = 8 ) or (
x = 2 &
y = 5 &
z = 5 &
t = 10 ) or (
x = 2 &
y = 6 &
z = 6 &
t = 6 ) or (
x = 3 &
y = 3 &
z = 4 &
t = 12 ) or (
x = 3 &
y = 3 &
z = 6 &
t = 6 ) or (
x = 3 &
y = 4 &
z = 4 &
t = 6 ) or (
x = 4 &
y = 4 &
z = 4 &
t = 4 ) ) )
Lm10:
for r being Integer st r >= 2 holds
1 / (r ^2) <= 1 / 4
Lm11:
for r being Integer st r > 2 holds
1 / (r ^2) <= 1 / 9
Lm12:
for x, y, z, t being Nat holds
( not (x ^2) + (2 * (y ^2)) = z ^2 or not (2 * (x ^2)) + (y ^2) = t ^2 or not x,y are_coprime )
theorem
for
x,
y,
z,
t being
positive Nat st
x <= y &
x <= z &
z <= t holds
( (
x + y = z * t &
z + t = x * y ) iff ( (
x = 1 &
y = 5 &
z = 2 &
t = 3 ) or (
x = 2 &
y = 2 &
z = 2 &
t = 2 ) ) )
deffunc H1( Nat) -> object = - 1;
deffunc H2( Nat) -> Nat = $1;
deffunc H3( Nat) -> set = 1 - H2($1);
deffunc H4( Nat) -> object = - 1;
deffunc H5( Nat) -> object = [H1($1),H2($1),H3($1),H4($1)];
definition
existence
ex b1 being Function of NAT,[:INT,INT,INT,INT:] st
for n being Nat holds b1 . n = [(- 1),n,(1 - n),(- 1)]
uniqueness
for b1, b2 being Function of NAT,[:INT,INT,INT,INT:] st ( for n being Nat holds b1 . n = [(- 1),n,(1 - n),(- 1)] ) & ( for n being Nat holds b2 . n = [(- 1),n,(1 - n),(- 1)] ) holds
b1 = b2
end;
set f = exampleSierpinski196 ;
theorem
for
a,
x,
y being
Complex holds
(
(x |^ 1) - (y |^ 1) = a iff
x = a + y ) ;