Lm1:
for X being non empty set
for P being a_partition of X
for x, y, z being set st x in P & y in P & z in x & z in y holds
x = y
by EQREL_1:70;
Lm3:
now for Y being set
for H being Hierarchy of Y st H is covering holds
for B being mutually-disjoint Subset-Family of Y st B c= H & ( for C being mutually-disjoint Subset-Family of Y st C c= H & union B c= union C holds
B = C ) holds
union B = Y
let Y be
set ;
for H being Hierarchy of Y st H is covering holds
for B being mutually-disjoint Subset-Family of Y st B c= H & ( for C being mutually-disjoint Subset-Family of Y st C c= H & union B c= union C holds
B = C ) holds
union B = Ylet H be
Hierarchy of
Y;
( H is covering implies for B being mutually-disjoint Subset-Family of Y st B c= H & ( for C being mutually-disjoint Subset-Family of Y st C c= H & union B c= union C holds
B = C ) holds
union B = Y )assume A1:
H is
covering
;
for B being mutually-disjoint Subset-Family of Y st B c= H & ( for C being mutually-disjoint Subset-Family of Y st C c= H & union B c= union C holds
B = C ) holds
union B = Ylet B be
mutually-disjoint Subset-Family of
Y;
( B c= H & ( for C being mutually-disjoint Subset-Family of Y st C c= H & union B c= union C holds
B = C ) implies union B = Y )assume that A2:
B c= H
and A3:
for
C being
mutually-disjoint Subset-Family of
Y st
C c= H &
union B c= union C holds
B = C
;
union B = Y
Y c= union B
proof
let y be
object ;
TARSKI:def 3 ( not y in Y or y in union B )
assume
y in Y
;
y in union B
then
y in union H
by A1, ABIAN:4;
then consider x being
set such that A4:
y in x
and A5:
x in H
by TARSKI:def 4;
now y in union B
defpred S1[
set ]
means $1
c= x;
consider D being
set such that A6:
for
a being
set holds
(
a in D iff (
a in B &
S1[
a] ) )
from XFAMILY:sch 1();
set C =
(B \ D) \/ {x};
A7:
B \ D c= (B \ D) \/ {x}
by XBOOLE_1:7;
A8:
{x} c= H
by A5, TARSKI:def 1;
assume A9:
not
y in union B
;
contradictionA10:
for
p being
set st
p in B & not
p in D &
p <> x holds
p misses x
A15:
for
p,
q being
set st
p in (B \ D) \/ {x} &
q in (B \ D) \/ {x} &
p <> q holds
p misses q
x in {x}
by TARSKI:def 1;
then A25:
x in (B \ D) \/ {x}
by XBOOLE_0:def 3;
A26:
union B c= union ((B \ D) \/ {x})
A29:
x in {x}
by TARSKI:def 1;
B \ D c= B
by XBOOLE_1:36;
then A30:
B \ D c= H
by A2;
then
(B \ D) \/ {x} c= H
by A8, XBOOLE_1:8;
then
(B \ D) \/ {x} is
mutually-disjoint Subset-Family of
Y
by A15, Def5, XBOOLE_1:1;
then A31:
B = (B \ D) \/ {x}
by A3, A30, A8, A26, XBOOLE_1:8;
{x} c= (B \ D) \/ {x}
by XBOOLE_1:7;
hence
contradiction
by A4, A9, A31, A29, TARSKI:def 4;
verum
end;
hence
y in union B
;
verum
end;
hence
union B = Y
by XBOOLE_0:def 10;
verum
end;