theorem
for
n1,
n2 being
Nat st
n1 ^2 = n2 ^2 holds
n1 = n2
AlgDef:
for n being Nat
for a, b being Real holds (rseq (0,1,a,b)) . n = 1 / ((a * n) + b)
Tele2:
for n being Nat holds Reci-seq1 . n = ((rseq (0,1,1,(- (1 / 2)))) . n) + ((- (rseq (0,1,1,(1 / 2)))) . n)
Surprise:
for n, m being non zero Nat st m ^2 divides SquarefreePart n holds
m = 1
ProdSqF:
for A being finite Subset of SetPrimes holds Product (A -bag) is square-free
definition
let n be non
zero Nat;
existence
ex b1 being Function of [:(bool (SetPrimes n)),(Seg n):],NAT st
for x being Element of [:(bool (SetPrimes n)),(Seg n):]
for A being finite Subset of SetPrimes
for k being Nat st x = [A,k] holds
b1 . x = (Product ((A,1) -bag)) * (k ^2)
uniqueness
for b1, b2 being Function of [:(bool (SetPrimes n)),(Seg n):],NAT st ( for x being Element of [:(bool (SetPrimes n)),(Seg n):]
for A being finite Subset of SetPrimes
for k being Nat st x = [A,k] holds
b1 . x = (Product ((A,1) -bag)) * (k ^2) ) & ( for x being Element of [:(bool (SetPrimes n)),(Seg n):]
for A being finite Subset of SetPrimes
for k being Nat st x = [A,k] holds
b2 . x = (Product ((A,1) -bag)) * (k ^2) ) holds
b1 = b2
end;