theorem :: REARRAN1:32

for n being Nat
for C, D being non empty finite set
for F being PartFunc of D,REAL
for A being RearrangmentGen of C st F is total & card D = card C & n in dom A holds
(FinS ((Rland (F,A)),C)) | n = FinS ((Rland (F,A)),(A . n))