theorem :: MESFUNC6:89

for X being non empty set
for S being SigmaField of X
for M being sigma_Measure of S
for f being PartFunc of X,REAL
for E, A being Element of S st E = dom f & f is E -measurable & M . A = 0 holds
Integral (M,(f | (E \ A))) = Integral (M,f) by MESFUNC5:95;