theorem Th50: :: MATRIX15:50
for l, m, n being Nat
for K being Field
for A being Matrix of n,m,K
for B being Matrix of n,l,K
for N being finite without_zero Subset of NAT st card N = n & N c= Seg m & n > 0 & Segm (A,(Seg n),N) = 1. (K,n) holds
ex X being Matrix of m,l,K st
( Segm (X,((Seg m) \ N),(Seg l)) = 0. (K,(m -' n),l) & Segm (X,N,(Seg l)) = B & X in Solutions_of (A,B) )