for X being BCK-algebra st {(0. X)} is commutativeIdeal of X holds ( ( for x, y being Element of X holds ( x \ y = x iff y \(y \ x)=0. X ) ) & ( for x, y being Element of X st x \ y = x holds y \ x = y ) & ( for x, y, a being Element of X st y <= a holds (a \ x)\(a \ y)= y \ x ) & ( for x, y being Element of X holds ( x \(y \(y \ x))= x \ y & (x \ y)\((x \ y)\ x)= x \ y ) ) & ( for x, y, a being Element of X st x <= a holds (a \ y)\((a \ y)\(a \ x))=(a \ y)\(x \ y) ) )