theorem Th25:
for
n being
natural non
empty number for
X being non
empty set for
S being non
empty non
void b1 PC-correct QC-correct QCLangSignature over
X for
Q being
language MSAlgebra over
S holds
(
{} in Args (
(In (( the connectives of S . (n + 5)), the carrier' of S)),
Q) & ( for
A being
Formula of
Q holds
(
<*A*> in Args (
(In (( the connectives of S . n), the carrier' of S)),
Q) & ( for
B being
Formula of
Q holds
(
<*A,B*> in Args (
(In (( the connectives of S . (n + 1)), the carrier' of S)),
Q) & ... &
<*A,B*> in Args (
(In (( the connectives of S . (n + 4)), the carrier' of S)),
Q) & ( for
x being
Element of
X holds
(
<*A*> in Args (
(In (( the quantifiers of S . (1,x)), the carrier' of S)),
Q) &
<*A*> in Args (
(In (( the quantifiers of S . (2,x)), the carrier' of S)),
Q) ) ) ) ) ) ) )