let L be non empty transitive RelStr ; :: thesis: for S being non empty full SubRelStr of L
for X being Subset of S st ex_inf_of X,L & "/\" (X,L) in the carrier of S holds
( ex_inf_of X,S & "/\" (X,S) = "/\" (X,L) )
let S be non empty full SubRelStr of L; :: thesis: for X being Subset of S st ex_inf_of X,L & "/\" (X,L) in the carrier of S holds
( ex_inf_of X,S & "/\" (X,S) = "/\" (X,L) )
let X be Subset of S; :: thesis: ( ex_inf_of X,L & "/\" (X,L) in the carrier of S implies ( ex_inf_of X,S & "/\" (X,S) = "/\" (X,L) ) )
assume that
A1: ex_inf_of X,L and
A2: "/\" (X,L) in the carrier of S ; :: thesis: ( ex_inf_of X,S & "/\" (X,S) = "/\" (X,L) )
reconsider a = "/\" (X,L) as Element of S by A2;

A3: now :: thesis: ( a is_<=_than X & ( for b being Element of S st b is_<=_than X holds
b <= a ) )

"/\" (X,L) is_<=_than X by A1, Def10;
hence a is_<=_than X by Th61; :: thesis: for b being Element of S st b is_<=_than X holds
b <= a
let b be Element of S; :: thesis: ( b is_<=_than X implies b <= a )
reconsider b9 = b as Element of L by Th58;
assume b is_<=_than X ; :: thesis: b <= a
then b9 is_<=_than X by Th62;
then b9 <= "/\" (X,L) by A1, Def10;
hence b <= a by Th60; :: thesis: verum

end;

consider a9 being Element of L such that
A4: X is_>=_than a9 and
A5: for b being Element of L st X is_>=_than b holds
b <= a9 and
for c being Element of L st X is_>=_than c & ( for b being Element of L st X is_>=_than b holds
b <= c ) holds
c = a9 by A1;
A6: a9 = "/\" (X,L) by A1, A4, A5, Def10;
thus ex_inf_of X,S :: thesis: "/\" (X,S) = "/\" (X,L)

proof

take a ; :: according to YELLOW_0:def 8 :: thesis: ( X is_>=_than a & ( for b being Element of S st X is_>=_than b holds
b <= a ) & ( for c being Element of S st X is_>=_than c & ( for b being Element of S st X is_>=_than b holds
b <= c ) holds
c = a ) )
thus ( a is_<=_than X & ( for b being Element of S st b is_<=_than X holds
b <= a ) ) by A3; :: thesis: for c being Element of S st X is_>=_than c & ( for b being Element of S st X is_>=_than b holds
b <= c ) holds
c = a
let c be Element of S; :: thesis: ( X is_>=_than c & ( for b being Element of S st X is_>=_than b holds
b <= c ) implies c = a )
reconsider c9 = c as Element of L by Th58;
assume X is_>=_than c ; :: thesis: ( ex b being Element of S st
( X is_>=_than b & not b <= c ) or c = a )
then A7: X is_>=_than c9 by Th62;
assume for b being Element of S st X is_>=_than b holds
b <= c ; :: thesis: c = a
then A8: a <= c by A3;

now :: thesis: for b being Element of L st X is_>=_than b holds
b <= c9

let b be Element of L; :: thesis: ( X is_>=_than b implies b <= c9 )
assume X is_>=_than b ; :: thesis: b <= c9
then A9: b <= a9 by A5;
a9 <= c9 by A6, A8, Th59;
hence b <= c9 by A9, ORDERS_2:3; :: thesis: verum

end;

hence c = a by A1, A7, Def10; :: thesis: verum

end;

hence "/\" (X,S) = "/\" (X,L) by A3, Def10; :: thesis: verum