let T be non empty TopSpace; for x, y being Element of T
for V being open Subset of T st x in V & not y in V holds
(chi (V, the carrier of T)) * ((0,1) --> (y,x)) = id Sierpinski_Space
let x, y be Element of T; for V being open Subset of T st x in V & not y in V holds
(chi (V, the carrier of T)) * ((0,1) --> (y,x)) = id Sierpinski_Space
let V be open Subset of T; ( x in V & not y in V implies (chi (V, the carrier of T)) * ((0,1) --> (y,x)) = id Sierpinski_Space )
assume that
A1:
x in V
and
A2:
not y in V
; (chi (V, the carrier of T)) * ((0,1) --> (y,x)) = id Sierpinski_Space
reconsider c = chi (V, the carrier of T) as Function of T,Sierpinski_Space by Th45;
A3:
c . x = 1
by A1, FUNCT_3:def 3;
A4:
the carrier of Sierpinski_Space = {0,{0}}
by WAYBEL18:def 9, CARD_1:49;
then reconsider i = (0,{0}) --> (y,x) as Function of Sierpinski_Space,T ;
A5:
i . 1 = x
by FUNCT_4:63, CARD_1:49;
A6:
c . y = 0
by A2, FUNCT_3:def 3;
A7:
i . 0 = y
by FUNCT_4:63;
hence
(chi (V, the carrier of T)) * ((0,1) --> (y,x)) = id Sierpinski_Space
by FUNCT_2:63, CARD_1:49; verum