let S, T be non empty TopSpace; for A being irreducible Subset of S
for B being Subset of T st A = B & TopStruct(# the carrier of S, the topology of S #) = TopStruct(# the carrier of T, the topology of T #) holds
B is irreducible
let A be irreducible Subset of S; for B being Subset of T st A = B & TopStruct(# the carrier of S, the topology of S #) = TopStruct(# the carrier of T, the topology of T #) holds
B is irreducible
let B be Subset of T; ( A = B & TopStruct(# the carrier of S, the topology of S #) = TopStruct(# the carrier of T, the topology of T #) implies B is irreducible )
assume that
A1:
A = B
and
A2:
TopStruct(# the carrier of S, the topology of S #) = TopStruct(# the carrier of T, the topology of T #)
; B is irreducible
( not A is empty & A is closed )
by YELLOW_8:def 3;
hence
( not B is empty & B is closed )
by A1, A2, TOPS_3:79; YELLOW_8:def 3 for b1, b2 being Element of K6( the carrier of T) holds
( not b1 is closed or not b2 is closed or not B = K20(K6( the carrier of T),b1,b2) or b1 = B or b2 = B )
let B1, B2 be Subset of T; ( not B1 is closed or not B2 is closed or not B = K20(K6( the carrier of T),B1,B2) or B1 = B or B2 = B )
assume that
A3:
( B1 is closed & B2 is closed )
and
A4:
B = B1 \/ B2
; ( B1 = B or B2 = B )
reconsider A1 = B1, A2 = B2 as Subset of S by A2;
( A1 is closed & A2 is closed )
by A2, A3, TOPS_3:79;
hence
( B1 = B or B2 = B )
by A1, A4, YELLOW_8:def 3; verum