let b, c be Real; ( ( for a being Real st a > 0 holds
b - a <= c ) implies b <= c )
assume A1:
for a being Real st a > 0 holds
b - a <= c
; b <= c
set d = b - c;
assume
b > c
; contradiction
then A2:
0 < b - c
by Lm21;
then
c + ((b - c) / 2) < c + (b - c)
by Lm10, Lm27;
then
c < b - ((b - c) / 2)
by Lm19;
hence
contradiction
by A1, A2; verum