let b, c be Real; ( ( for a being Real st a < 0 holds
c <= b - a ) implies b >= c )
assume A1:
for a being Real st a < 0 holds
b - a >= c
; b >= c
set d = b - c;
assume
b < c
; contradiction
then A2:
0 > b - c
by Lm23;
then
(- (b - c)) / 2 < - (b - c)
by Lm27;
then
b + (- ((b - c) / 2)) < b + (- (b - c))
by Lm10;
then
b - ((b - c) / 2) < b - (b - c)
;
hence
contradiction
by A1, A2; verum