let b, c be Real; ( ( for a being Real st a < 0 holds
b + a <= c ) implies b <= c )
assume A1:
for a being Real st a < 0 holds
b + a <= c
; b <= c
set d = c - b;
assume
c < b
; contradiction
then A2:
0 > c - b
by Lm23;
then
(- (c - b)) / 2 < - (c - b)
by Lm27;
then
c + (- ((c - b) / 2)) < c + (- (c - b))
by Lm10;
then
c - ((c - b) / 2) < c - (c - b)
;
then
c < b + ((c - b) / 2)
by Lm16;
hence
contradiction
by A1, A2; verum