let b, c be Real; ( ( for a being Real st a > 0 holds
c <= b + a ) implies c <= b )
assume A1:
for a being Real st a > 0 holds
b + a >= c
; c <= b
set d = c - b;
assume
b < c
; contradiction
then A2:
0 < c - b
by Lm21;
then
b + ((c - b) / 2) < b + (c - b)
by Lm10, Lm27;
hence
contradiction
by A1, A2; verum