let k be Nat; for p being Prime st p * p <= k & k < 169 & not p = 2 & not p = 3 & not p = 5 & not p = 7 holds
p = 11
let p be Prime; ( p * p <= k & k < 169 & not p = 2 & not p = 3 & not p = 5 & not p = 7 implies p = 11 )
assume
( p * p <= k & k < 169 )
; ( p = 2 or p = 3 or p = 5 or p = 7 or p = 11 )
then
p * p < 13 * 13
by XXREAL_0:2;
hence
( p = 2 or p = 3 or p = 5 or p = 7 or p = 11 )
by Ttool13a, NAT_4:1; verum