let X1, X2 be set ; ( ( for x being set holds
( x in X1 iff P1[x] ) ) & ( for x being set holds
( x in X2 iff P1[x] ) ) implies X1 = X2 )
assume that
A1:
for x being set holds
( x in X1 iff P1[x] )
and
A2:
for x being set holds
( x in X2 iff P1[x] )
; X1 = X2
thus
X1 = X2
from XFAMILY:sch 2(A1, A2); verum