let M be non empty set ; ( ( for X being set st X in M holds
X <> {} ) & ( for X, Y being set st X in M & Y in M & X <> Y holds
X misses Y ) implies ex Choice being set st
for X being set st X in M holds
ex x being object st Choice /\ X = {x} )
assume that
A1:
for X being set st X in M holds
X <> {}
and
A2:
for X, Y being set st X in M & Y in M & X <> Y holds
X misses Y
; ex Choice being set st
for X being set st X in M holds
ex x being object st Choice /\ X = {x}
consider R being Relation such that
A3:
R well_orders union M
by Th11;
A4:
R is_reflexive_in union M
by A3;
A5:
R is_connected_in union M
by A3;
defpred S1[ object , object ] means ex D1 being set st
( D1 = $1 & $2 in D1 & ( for z being object st z in D1 holds
[$2,z] in R ) );
A6:
R is_antisymmetric_in union M
by A3;
A7:
for x, y, z being object st x in M & S1[x,y] & S1[x,z] holds
y = z
proof
let x,
y,
z be
object ;
( x in M & S1[x,y] & S1[x,z] implies y = z )
assume A8:
x in M
;
( not S1[x,y] or not S1[x,z] or y = z )
given X being
set such that A9:
X = x
and A10:
y in X
and A11:
for
u being
object st
u in X holds
[y,u] in R
;
( not S1[x,z] or y = z )
A12:
y in union M
by A8, A10, TARSKI:def 4, A9;
given X being
set such that A13:
X = x
and A14:
z in X
and A15:
for
u being
object st
u in X holds
[z,u] in R
;
y = z
A16:
z in union M
by A8, A14, TARSKI:def 4, A13;
(
[y,z] in R &
[z,y] in R )
by A10, A11, A14, A15, A9, A13;
hence
y = z
by A6, A12, A16;
verum
end;
A17:
R is_well_founded_in union M
by A3;
A18:
for x being object st x in M holds
ex y being object st S1[x,y]
proof
let x be
object ;
( x in M implies ex y being object st S1[x,y] )
assume A19:
x in M
;
ex y being object st S1[x,y]
reconsider xx =
x as
set by TARSKI:1;
A20:
xx c= union M
by ZFMISC_1:74, A19;
x <> {}
by A1, A19;
then consider y being
object such that A21:
y in xx
and A22:
R -Seg y misses xx
by A17, A20;
take
y
;
S1[x,y]
take
xx
;
( xx = x & y in xx & ( for z being object st z in xx holds
[y,z] in R ) )
thus
xx = x
;
( y in xx & ( for z being object st z in xx holds
[y,z] in R ) )
thus
y in xx
by A21;
for z being object st z in xx holds
[y,z] in R
let z be
object ;
( z in xx implies [y,z] in R )
assume A23:
z in xx
;
[y,z] in R
then A24:
not
z in R -Seg y
by A22, XBOOLE_0:3;
( not
y <> z or
[y,z] in R or
[z,y] in R )
by A5, A20, A21, A23;
hence
[y,z] in R
by A4, A20, A23, A24, WELLORD1:1;
verum
end;
consider f being Function such that
A25:
( dom f = M & ( for x being object st x in M holds
S1[x,f . x] ) )
from FUNCT_1:sch 2(A7, A18);
take Choice = rng f; for X being set st X in M holds
ex x being object st Choice /\ X = {x}
let X be set ; ( X in M implies ex x being object st Choice /\ X = {x} )
assume A26:
X in M
; ex x being object st Choice /\ X = {x}
take x = f . X; Choice /\ X = {x}
thus
Choice /\ X c= {x}
XBOOLE_0:def 10 {x} c= Choice /\ Xproof
let y be
object ;
TARSKI:def 3 ( not y in Choice /\ X or y in {x} )
assume A27:
y in Choice /\ X
;
y in {x}
then A28:
y in X
by XBOOLE_0:def 4;
y in Choice
by A27, XBOOLE_0:def 4;
then consider z being
object such that A29:
z in dom f
and A30:
y = f . z
by FUNCT_1:def 3;
reconsider z =
z as
set by TARSKI:1;
assume
not
y in {x}
;
contradiction
then
X <> z
by A30, TARSKI:def 1;
then
X misses z
by A2, A25, A26, A29;
then A31:
X /\ z = {}
;
S1[
z,
f . z]
by A25, A29;
then
f . z in z
;
hence
contradiction
by A28, A30, A31, XBOOLE_0:def 4;
verum
end;
let y be object ; TARSKI:def 3 ( not y in {x} or y in Choice /\ X )
assume
y in {x}
; y in Choice /\ X
then A32:
y = x
by TARSKI:def 1;
S1[X,f . X]
by A25, A26;
then A33:
y in X
by A32;
y in Choice
by A25, A26, A32, FUNCT_1:def 3;
hence
y in Choice /\ X
by A33, XBOOLE_0:def 4; verum