let A, B be Ordinal; ( RelIncl A, RelIncl B are_isomorphic implies A = B )
A1:
field (RelIncl A) = A
by Def1;
assume A2:
RelIncl A, RelIncl B are_isomorphic
; A = B
assume
A <> B
; contradiction
then A6:
( A in B or B in A )
by ORDINAL1:14;
then
B = (RelIncl A) -Seg B
by A3, Th3;
then
RelIncl B = (RelIncl A) |_2 ((RelIncl A) -Seg B)
by A1, Th1, WELLORD1:9;
hence
contradiction
by A2, A6, A3, A1, WELLORD1:46; verum