let a, b be object ; for R being Relation st R is well-ordering & b in R -Seg a holds
(R |_2 (R -Seg a)) -Seg b = R -Seg b
let R be Relation; ( R is well-ordering & b in R -Seg a implies (R |_2 (R -Seg a)) -Seg b = R -Seg b )
assume that
A1:
R is well-ordering
and
A2:
b in R -Seg a
; (R |_2 (R -Seg a)) -Seg b = R -Seg b
set S = R |_2 (R -Seg a);
now for c being object st c in R -Seg b holds
c in (R |_2 (R -Seg a)) -Seg blet c be
object ;
( c in R -Seg b implies c in (R |_2 (R -Seg a)) -Seg b )assume A3:
c in R -Seg b
;
c in (R |_2 (R -Seg a)) -Seg bthen A4:
[c,b] in R
by Th1;
A5:
[b,a] in R
by A2, Th1;
then A6:
[c,a] in R
by A1, A4, Lm2;
A7:
c <> b
by A3, Th1;
then
c <> a
by A1, A4, A5, Lm3;
then
c in R -Seg a
by A6, Th1;
then
[c,b] in [:(R -Seg a),(R -Seg a):]
by A2, ZFMISC_1:87;
then
[c,b] in R |_2 (R -Seg a)
by A4, XBOOLE_0:def 4;
hence
c in (R |_2 (R -Seg a)) -Seg b
by A7, Th1;
verum end;
then A8:
R -Seg b c= (R |_2 (R -Seg a)) -Seg b
;
then
(R |_2 (R -Seg a)) -Seg b c= R -Seg b
;
hence
(R |_2 (R -Seg a)) -Seg b = R -Seg b
by A8; verum