let R be RelStr ; for X, Y being well_founded Subset of R st X is lower holds
X \/ Y is well_founded Subset of R
let X, Y be well_founded Subset of R; ( X is lower implies X \/ Y is well_founded Subset of R )
set r = the InternalRel of R;
assume A1:
X is lower
; X \/ Y is well_founded Subset of R
reconsider XY = X \/ Y as Subset of R ;
A2:
the InternalRel of R is_well_founded_in Y
by Def3;
A3:
the InternalRel of R is_well_founded_in X
by Def3;
XY is well_founded
proof
let Z be
set ;
WELLORD1:def 3,
WELLFND1:def 3 ( not Z c= XY or Z = {} or ex b1 being object st
( b1 in Z & the InternalRel of R -Seg b1 misses Z ) )
assume that A4:
Z c= XY
and A5:
Z <> {}
;
ex b1 being object st
( b1 in Z & the InternalRel of R -Seg b1 misses Z )
set XZ =
X /\ Z;
A6:
X /\ Z c= X
by XBOOLE_1:17;
per cases
( X /\ Z = {} or X /\ Z <> {} )
;
suppose
X /\ Z <> {}
;
ex b1 being object st
( b1 in Z & the InternalRel of R -Seg b1 misses Z )then consider a being
object such that A7:
a in X /\ Z
and A8:
the
InternalRel of
R -Seg a misses X /\ Z
by A3, A6;
A9:
a in X
by A7, XBOOLE_0:def 4;
take
a
;
( a in Z & the InternalRel of R -Seg a misses Z )thus
a in Z
by A7, XBOOLE_0:def 4;
the InternalRel of R -Seg a misses Zassume
( the InternalRel of R -Seg a) /\ Z <> {}
;
XBOOLE_0:def 7 contradictionthen consider b being
object such that A10:
b in ( the InternalRel of R -Seg a) /\ Z
by XBOOLE_0:def 1;
A11:
b in Z
by A10, XBOOLE_0:def 4;
A12:
b in the
InternalRel of
R -Seg a
by A10, XBOOLE_0:def 4;
then
[b,a] in the
InternalRel of
R
by WELLORD1:1;
then
b in X
by A1, A9;
then
b in X /\ Z
by A11, XBOOLE_0:def 4;
hence
contradiction
by A8, A12, XBOOLE_0:3;
verum end; end;
end;
hence
X \/ Y is well_founded Subset of R
; verum