let L be lower-bounded with_suprema Poset; for a, b being auxiliary(iii) Relation of L holds a /\ b is auxiliary(iii) Relation of L
let a, b be auxiliary(iii) Relation of L; a /\ b is auxiliary(iii) Relation of L
reconsider ab = a /\ b as Relation of L ;
for x, y, z being Element of L st [x,z] in ab & [y,z] in ab holds
[(x "\/" y),z] in ab
proof
let x,
y,
z be
Element of
L;
( [x,z] in ab & [y,z] in ab implies [(x "\/" y),z] in ab )
assume that A1:
[x,z] in ab
and A2:
[y,z] in ab
;
[(x "\/" y),z] in ab
A3:
[x,z] in a
by A1, XBOOLE_0:def 4;
A4:
[x,z] in b
by A1, XBOOLE_0:def 4;
A5:
[y,z] in a
by A2, XBOOLE_0:def 4;
A6:
[y,z] in b
by A2, XBOOLE_0:def 4;
A7:
[(x "\/" y),z] in a
by A3, A5, Def5;
[(x "\/" y),z] in b
by A4, A6, Def5;
hence
[(x "\/" y),z] in ab
by A7, XBOOLE_0:def 4;
verum
end;
hence
a /\ b is auxiliary(iii) Relation of L
by Def5; verum