set A = AuxBottom L;
A1:
AuxBottom L is auxiliary(i)
A2:
AuxBottom L is auxiliary(ii)
proof
let x,
y,
z,
u be
Element of
L;
WAYBEL_4:def 4 ( u <= x & [x,y] in AuxBottom L & y <= z implies [u,z] in AuxBottom L )
assume that A3:
u <= x
and A4:
[x,y] in AuxBottom L
and
y <= z
;
[u,z] in AuxBottom L
A5:
x = Bottom L
by A4, Def9;
Bottom L <= u
by YELLOW_0:44;
then
u = Bottom L
by A3, A5, ORDERS_2:2;
hence
[u,z] in AuxBottom L
by Def9;
verum
end;
A6:
AuxBottom L is auxiliary(iii)
proof
let x,
y,
z be
Element of
L;
WAYBEL_4:def 5 ( [x,z] in AuxBottom L & [y,z] in AuxBottom L implies [(x "\/" y),z] in AuxBottom L )
assume that A7:
[x,z] in AuxBottom L
and A8:
[y,z] in AuxBottom L
;
[(x "\/" y),z] in AuxBottom L
A9:
y = Bottom L
by A8, Def9;
then
x <= y
by A7, Def9;
then
x "\/" y = Bottom L
by A9, YELLOW_0:24;
hence
[(x "\/" y),z] in AuxBottom L
by Def9;
verum
end;
for x being Element of L holds [(Bottom L),x] in AuxBottom L
by Def9;
then
AuxBottom L is auxiliary(iv)
;
hence
AuxBottom L is auxiliary
by A1, A2, A6; verum