let L be non empty Poset; for R being auxiliary(i) auxiliary(ii) Relation of L
for C being non empty strict_chain of R
for X being Subset of C st ex_sup_of X,L & C is maximal & not "\/" (X,L) in C holds
ex cs being Element of L st
( cs in C & "\/" (X,L) < cs & not [("\/" (X,L)),cs] in R & ex cs1 being Element of (subrelstr C) st
( cs = cs1 & X is_<=_than cs1 & ( for a being Element of (subrelstr C) st X is_<=_than a holds
cs1 <= a ) ) )
let R be auxiliary(i) auxiliary(ii) Relation of L; for C being non empty strict_chain of R
for X being Subset of C st ex_sup_of X,L & C is maximal & not "\/" (X,L) in C holds
ex cs being Element of L st
( cs in C & "\/" (X,L) < cs & not [("\/" (X,L)),cs] in R & ex cs1 being Element of (subrelstr C) st
( cs = cs1 & X is_<=_than cs1 & ( for a being Element of (subrelstr C) st X is_<=_than a holds
cs1 <= a ) ) )
let C be non empty strict_chain of R; for X being Subset of C st ex_sup_of X,L & C is maximal & not "\/" (X,L) in C holds
ex cs being Element of L st
( cs in C & "\/" (X,L) < cs & not [("\/" (X,L)),cs] in R & ex cs1 being Element of (subrelstr C) st
( cs = cs1 & X is_<=_than cs1 & ( for a being Element of (subrelstr C) st X is_<=_than a holds
cs1 <= a ) ) )
let X be Subset of C; ( ex_sup_of X,L & C is maximal & not "\/" (X,L) in C implies ex cs being Element of L st
( cs in C & "\/" (X,L) < cs & not [("\/" (X,L)),cs] in R & ex cs1 being Element of (subrelstr C) st
( cs = cs1 & X is_<=_than cs1 & ( for a being Element of (subrelstr C) st X is_<=_than a holds
cs1 <= a ) ) ) )
assume that
A1:
ex_sup_of X,L
and
A2:
C is maximal
; ( "\/" (X,L) in C or ex cs being Element of L st
( cs in C & "\/" (X,L) < cs & not [("\/" (X,L)),cs] in R & ex cs1 being Element of (subrelstr C) st
( cs = cs1 & X is_<=_than cs1 & ( for a being Element of (subrelstr C) st X is_<=_than a holds
cs1 <= a ) ) ) )
set s = "\/" (X,L);
A3:
C c= C \/ {("\/" (X,L))}
by XBOOLE_1:7;
assume A4:
not "\/" (X,L) in C
; ex cs being Element of L st
( cs in C & "\/" (X,L) < cs & not [("\/" (X,L)),cs] in R & ex cs1 being Element of (subrelstr C) st
( cs = cs1 & X is_<=_than cs1 & ( for a being Element of (subrelstr C) st X is_<=_than a holds
cs1 <= a ) ) )
then
not C \/ {("\/" (X,L))} c= C
by ZFMISC_1:39;
then A5:
C \/ {("\/" (X,L))} is not strict_chain of R
by A3, A2;
ex cs being Element of L st
( cs in C & "\/" (X,L) < cs & not [("\/" (X,L)),cs] in R )
proof
A6:
for
a being
Element of
L st
a in C & not
[a,("\/" (X,L))] in R & not
[("\/" (X,L)),a] in R holds
ex
cs being
Element of
L st
(
cs in C &
"\/" (
X,
L)
< cs & not
[("\/" (X,L)),cs] in R )
proof
let a be
Element of
L;
( a in C & not [a,("\/" (X,L))] in R & not [("\/" (X,L)),a] in R implies ex cs being Element of L st
( cs in C & "\/" (X,L) < cs & not [("\/" (X,L)),cs] in R ) )
assume that A7:
a in C
and A8:
not
[a,("\/" (X,L))] in R
and A9:
not
[("\/" (X,L)),a] in R
;
ex cs being Element of L st
( cs in C & "\/" (X,L) < cs & not [("\/" (X,L)),cs] in R )
take
a
;
( a in C & "\/" (X,L) < a & not [("\/" (X,L)),a] in R )
thus
a in C
by A7;
( "\/" (X,L) < a & not [("\/" (X,L)),a] in R )
a is_>=_than X
then
"\/" (
X,
L)
<= a
by A1, YELLOW_0:def 9;
hence
"\/" (
X,
L)
< a
by A4, A7, ORDERS_2:def 6;
not [("\/" (X,L)),a] in R
thus
not
[("\/" (X,L)),a] in R
by A9;
verum
end;
consider a,
b being
set such that A13:
a in C \/ {("\/" (X,L))}
and A14:
b in C \/ {("\/" (X,L))}
and A15:
not
[a,b] in R
and A16:
a <> b
and A17:
not
[b,a] in R
by A5, Def3;
reconsider a =
a,
b =
b as
Element of
L by A13, A14;
end;
then consider cs being Element of L such that
A18:
cs in C
and
A19:
"\/" (X,L) < cs
and
A20:
not [("\/" (X,L)),cs] in R
;
take
cs
; ( cs in C & "\/" (X,L) < cs & not [("\/" (X,L)),cs] in R & ex cs1 being Element of (subrelstr C) st
( cs = cs1 & X is_<=_than cs1 & ( for a being Element of (subrelstr C) st X is_<=_than a holds
cs1 <= a ) ) )
thus
( cs in C & "\/" (X,L) < cs & not [("\/" (X,L)),cs] in R )
by A18, A19, A20; ex cs1 being Element of (subrelstr C) st
( cs = cs1 & X is_<=_than cs1 & ( for a being Element of (subrelstr C) st X is_<=_than a holds
cs1 <= a ) )
reconsider cs1 = cs as Element of (subrelstr C) by A18, YELLOW_0:def 15;
take
cs1
; ( cs = cs1 & X is_<=_than cs1 & ( for a being Element of (subrelstr C) st X is_<=_than a holds
cs1 <= a ) )
thus
cs = cs1
; ( X is_<=_than cs1 & ( for a being Element of (subrelstr C) st X is_<=_than a holds
cs1 <= a ) )
A21:
"\/" (X,L) <= cs
by A19, ORDERS_2:def 6;
thus
X is_<=_than cs1
for a being Element of (subrelstr C) st X is_<=_than a holds
cs1 <= a
let a be Element of (subrelstr C); ( X is_<=_than a implies cs1 <= a )
reconsider a0 = a as Element of L by YELLOW_0:58;
A22:
the carrier of (subrelstr C) = C
by YELLOW_0:def 15;
assume
X is_<=_than a
; cs1 <= a
then
X is_<=_than a0
by A22, YELLOW_0:62;
then A23:
"\/" (X,L) <= a0
by A1, YELLOW_0:def 9;
A24:
cs <= cs
;
( [cs1,a] in R or a = cs1 or [a,cs1] in R )
by A22, Def3;
then
cs <= a0
by A20, A23, A24, WAYBEL_4:def 3, WAYBEL_4:def 4;
hence
cs1 <= a
by YELLOW_0:60; verum