let L1 be lower-bounded continuous sup-Semilattice; :: thesis: for T being Scott TopAugmentation of L1
for b being Basis of T holds { (wayabove (inf u)) where u is Subset of T : u in b } is Basis of T

let T be Scott TopAugmentation of L1; :: thesis: for b being Basis of T holds { (wayabove (inf u)) where u is Subset of T : u in b } is Basis of T
let b be Basis of T; :: thesis: { (wayabove (inf u)) where u is Subset of T : u in b } is Basis of T
set b2 = { (wayabove (inf u)) where u is Subset of T : u in b } ;
{ (wayabove (inf u)) where u is Subset of T : u in b } c= bool the carrier of T
proof
let z be object ; :: according to TARSKI:def 3 :: thesis: ( not z in { (wayabove (inf u)) where u is Subset of T : u in b } or z in bool the carrier of T )
assume z in { (wayabove (inf u)) where u is Subset of T : u in b } ; :: thesis: z in bool the carrier of T
then ex u being Subset of T st
( z = wayabove (inf u) & u in b ) ;
hence z in bool the carrier of T ; :: thesis: verum
end;
then reconsider b2 = { (wayabove (inf u)) where u is Subset of T : u in b } as Subset-Family of T ;
reconsider b1 = { (wayabove x) where x is Element of T : verum } as Basis of T by WAYBEL11:45;
A1: now :: thesis: for A being Subset of T st A is open holds
for a being Point of T st a in A holds
ex u being Element of K32( the carrier of T) st
( u in b2 & a in u & u c= A )
let A be Subset of T; :: thesis: ( A is open implies for a being Point of T st a in A holds
ex u being Element of K32( the carrier of T) st
( u in b2 & a in u & u c= A ) )

assume A2: A is open ; :: thesis: for a being Point of T st a in A holds
ex u being Element of K32( the carrier of T) st
( u in b2 & a in u & u c= A )

let a be Point of T; :: thesis: ( a in A implies ex u being Element of K32( the carrier of T) st
( u in b2 & a in u & u c= A ) )

assume a in A ; :: thesis: ex u being Element of K32( the carrier of T) st
( u in b2 & a in u & u c= A )

then consider C being Subset of T such that
A3: C in b1 and
A4: a in C and
A5: C c= A by A2, YELLOW_9:31;
C is open by A3, YELLOW_8:10;
then consider D being Subset of T such that
A6: D in b and
A7: a in D and
A8: D c= C by A4, YELLOW_9:31;
D is open by A6, YELLOW_8:10;
then consider E being Subset of T such that
A9: E in b1 and
A10: a in E and
A11: E c= D by A7, YELLOW_9:31;
consider z being Element of T such that
A12: E = wayabove z by A9;
take u = wayabove (inf D); :: thesis: ( u in b2 & a in u & u c= A )
thus u in b2 by A6; :: thesis: ( a in u & u c= A )
reconsider a1 = a as Element of T ;
consider x being Element of T such that
A13: C = wayabove x by A3;
z << a1 by A10, A12, WAYBEL_3:8;
then consider y being Element of T such that
A14: z << y and
A15: y << a1 by WAYBEL_4:52;
( inf D is_<=_than D & y in wayabove z ) by A14, WAYBEL_3:8, YELLOW_0:33;
then inf D <= y by A11, A12, LATTICE3:def 8;
then inf D << a1 by A15, WAYBEL_3:2;
hence a in u by WAYBEL_3:8; :: thesis: u c= A
A16: wayabove x c= uparrow x by WAYBEL_3:11;
( ex_inf_of uparrow x,T & ex_inf_of D,T ) by YELLOW_0:17;
then inf (uparrow x) <= inf D by A13, A8, A16, XBOOLE_1:1, YELLOW_0:35;
then x <= inf D by WAYBEL_0:39;
then wayabove (inf D) c= C by A13, WAYBEL_3:12;
hence u c= A by A5; :: thesis: verum
end;
b2 c= the topology of T
proof
let z be object ; :: according to TARSKI:def 3 :: thesis: ( not z in b2 or z in the topology of T )
assume z in b2 ; :: thesis: z in the topology of T
then consider u being Subset of T such that
A17: z = wayabove (inf u) and
u in b ;
wayabove (inf u) is open by WAYBEL11:36;
hence z in the topology of T by A17, PRE_TOPC:def 2; :: thesis: verum
end;
hence { (wayabove (inf u)) where u is Subset of T : u in b } is Basis of T by A1, YELLOW_9:32; :: thesis: verum