let F be Field; for U, V being VectSp of F
for B being non empty Subset of U
for f being Function of B,V st f is one-to-one holds
for v being Element of V st v in rng f holds
f " {v} = {((f ") . v)}
let U, V be VectSp of F; for B being non empty Subset of U
for f being Function of B,V st f is one-to-one holds
for v being Element of V st v in rng f holds
f " {v} = {((f ") . v)}
let B be non empty Subset of U; for f being Function of B,V st f is one-to-one holds
for v being Element of V st v in rng f holds
f " {v} = {((f ") . v)}
let f be Function of B,V; ( f is one-to-one implies for v being Element of V st v in rng f holds
f " {v} = {((f ") . v)} )
assume A:
f is one-to-one
; for v being Element of V st v in rng f holds
f " {v} = {((f ") . v)}
let v be Element of V; ( v in rng f implies f " {v} = {((f ") . v)} )
assume
v in rng f
; f " {v} = {((f ") . v)}
then consider x being object such that
B:
f " {v} = {x}
by A, FUNCT_1:74;
x in f " {v}
by B, TARSKI:def 1;
then C:
( x in dom f & f . x in {v} )
by FUNCT_1:def 7;
then
v = f . x
by TARSKI:def 1;
hence
f " {v} = {((f ") . v)}
by B, A, C, FUNCT_1:34; verum