let T be non empty TopSpace; ( T is T_1 iff for p being Point of T holds {p} is closed )
thus
( T is T_1 implies for p being Point of T holds {p} is closed )
( ( for p being Point of T holds {p} is closed ) implies T is T_1 )
assume A18:
for p being Point of T holds {p} is closed
; T is T_1
for p, q being Point of T st not p = q holds
ex W, V being Subset of T st
( W is open & V is open & p in W & not q in W & q in V & not p in V )
proof
let p,
q be
Point of
T;
( not p = q implies ex W, V being Subset of T st
( W is open & V is open & p in W & not q in W & q in V & not p in V ) )
consider V,
W being
Subset of
T such that A19:
V = {p} `
and A20:
W = {q} `
;
p in {p}
by TARSKI:def 1;
then A21:
not
p in V
by A19, XBOOLE_0:def 5;
assume A22:
not
p = q
;
ex W, V being Subset of T st
( W is open & V is open & p in W & not q in W & q in V & not p in V )
then
not
p in {q}
by TARSKI:def 1;
then A23:
p in W
by A20, XBOOLE_0:def 5;
q in {q}
by TARSKI:def 1;
then A24:
not
q in W
by A20, XBOOLE_0:def 5;
not
q in {p}
by A22, TARSKI:def 1;
then A25:
q in V
by A19, XBOOLE_0:def 5;
(
{p} is
closed &
{q} is
closed )
by A18;
hence
ex
W,
V being
Subset of
T st
(
W is
open &
V is
open &
p in W & not
q in W &
q in V & not
p in V )
by A19, A20, A23, A24, A25, A21;
verum
end;
hence
T is T_1
; verum