let n, ni be non zero Element of NAT ; :: thesis: ( ni divides n implies ni -roots_of_1 c= n -roots_of_1 )
assume ni divides n ; :: thesis: ni -roots_of_1 c= n -roots_of_1
then consider k being Nat such that
A1: n = ni * k by NAT_D:def 3;
reconsider k = k as Element of NAT by ORDINAL1:def 12;
for x being object st x in ni -roots_of_1 holds
x in n -roots_of_1
proof end;
hence ni -roots_of_1 c= n -roots_of_1 ; :: thesis: verum