let X be set ; for R, S being Relation of X holds R * S = { [x,y] where x, y is Element of X : ex z being Element of X st
( [x,z] in R & [z,y] in S ) }
let R, S be Relation of X; R * S = { [x,y] where x, y is Element of X : ex z being Element of X st
( [x,z] in R & [z,y] in S ) }
reconsider RS = R * S as Relation of X ;
A1:
R * S c= { [x,y] where x, y is Element of X : ex z being Element of X st
( [x,z] in R & [z,y] in S ) }
proof
let t be
object ;
TARSKI:def 3 ( not t in R * S or t in { [x,y] where x, y is Element of X : ex z being Element of X st
( [x,z] in R & [z,y] in S ) } )
assume A1:
t in R * S
;
t in { [x,y] where x, y is Element of X : ex z being Element of X st
( [x,z] in R & [z,y] in S ) }
consider x1,
x2 being
object such that
x1 in X
and A2:
x2 in X
and A3:
t = [x1,x2]
by A1, ZFMISC_1:def 2;
consider z being
object such that A4:
[x1,z] in R
and A5:
[z,x2] in S
by A1, A3, RELAT_1:def 8;
reconsider x1 =
x1,
x2 =
x2,
z1 =
z as
Element of
X by A2, A4, ZFMISC_1:87;
(
[x1,z1] in R &
[z1,x2] in S )
by A4, A5;
hence
t in { [x,y] where x, y is Element of X : ex z being Element of X st
( [x,z] in R & [z,y] in S ) }
by A3;
verum
end;
{ [x,y] where x, y is Element of X : ex z being Element of X st
( [x,z] in R & [z,y] in S ) } c= R * S
proof
let t be
object ;
TARSKI:def 3 ( not t in { [x,y] where x, y is Element of X : ex z being Element of X st
( [x,z] in R & [z,y] in S ) } or t in R * S )
assume
t in { [x,y] where x, y is Element of X : ex z being Element of X st
( [x,z] in R & [z,y] in S ) }
;
t in R * S
then
ex
x,
y being
Element of
X st
(
t = [x,y] & ex
z being
Element of
X st
(
[x,z] in R &
[z,y] in S ) )
;
hence
t in R * S
by RELAT_1:def 8;
verum
end;
hence
R * S = { [x,y] where x, y is Element of X : ex z being Element of X st
( [x,z] in R & [z,y] in S ) }
by A1; verum