let j be Nat; for f, g being non empty FinSequence of (TOP-REAL 2) st 1 <= j & j + 1 < len g holds
LSeg ((f ^' g),((len f) + j)) = LSeg (g,(j + 1))
let f, g be non empty FinSequence of (TOP-REAL 2); ( 1 <= j & j + 1 < len g implies LSeg ((f ^' g),((len f) + j)) = LSeg (g,(j + 1)) )
assume that
A1:
1 <= j
and
A2:
j + 1 < len g
; LSeg ((f ^' g),((len f) + j)) = LSeg (g,(j + 1))
A3: (f ^' g) /. (((len f) + j) + 1) =
(f ^' g) /. ((len f) + (j + 1))
.=
g /. ((j + 1) + 1)
by A2, FINSEQ_6:160, NAT_1:11
;
j + 0 <= j + 1
by XREAL_1:6;
then
j < len g
by A2, XXREAL_0:2;
then A4:
(f ^' g) /. ((len f) + j) = g /. (j + 1)
by A1, FINSEQ_6:160;
A5:
1 <= j + 1
by NAT_1:11;
(len f) + (j + 1) < (len f) + (len g)
by A2, XREAL_1:6;
then
((len f) + j) + 1 < (len (f ^' g)) + 1
by FINSEQ_6:139;
then A6:
((len f) + j) + 1 <= len (f ^' g)
by NAT_1:13;
A7:
(j + 1) + 1 <= len g
by A2, NAT_1:13;
j <= (len f) + j
by NAT_1:11;
then
1 <= (len f) + j
by A1, XXREAL_0:2;
hence LSeg ((f ^' g),((len f) + j)) =
LSeg (((f ^' g) /. ((len f) + j)),((f ^' g) /. (((len f) + j) + 1)))
by A6, TOPREAL1:def 3
.=
LSeg (g,(j + 1))
by A4, A5, A3, A7, TOPREAL1:def 3
;
verum