let M be non empty MetrSpace; for X being Subset of (TopSpaceMetr M)
for x being object holds
( x in Cl X iff ex S being sequence of M st
( ( for n being Nat holds S . n in X ) & S is convergent & lim S = x ) )
let X be Subset of (TopSpaceMetr M); for x being object holds
( x in Cl X iff ex S being sequence of M st
( ( for n being Nat holds S . n in X ) & S is convergent & lim S = x ) )
let x be object ; ( x in Cl X iff ex S being sequence of M st
( ( for n being Nat holds S . n in X ) & S is convergent & lim S = x ) )
hereby ( ex S being sequence of M st
( ( for n being Nat holds S . n in X ) & S is convergent & lim S = x ) implies x in Cl X )
assume A1:
x in Cl X
;
ex S being sequence of M st
( ( for n being Nat holds S . n in X ) & S is convergent & lim S = x )reconsider x0 =
x as
Element of
M by A1;
defpred S1[
Element of
NAT ,
object ]
means ( $2
in X & $2
in Ball (
x0,
(1 / ($1 + 1))) );
A2:
for
n being
Element of
NAT ex
p being
Element of
M st
S1[
n,
p]
proof
let n be
Element of
NAT ;
ex p being Element of M st S1[n,p]
set r = 1
/ (n + 1);
reconsider G =
Ball (
x0,
(1 / (n + 1))) as
Subset of
(TopSpaceMetr M) ;
dist (
x0,
x0)
= 0
by METRIC_1:1;
then
(
G is
open &
x0 in G )
by METRIC_1:11, TOPMETR:14;
then
X meets Ball (
x0,
(1 / (n + 1)))
by A1, PRE_TOPC:def 7;
then consider p being
object such that A3:
p in X /\ (Ball (x0,(1 / (n + 1))))
by XBOOLE_0:def 1;
reconsider p =
p as
Element of
M by A3;
take
p
;
S1[n,p]
thus
S1[
n,
p]
by A3, XBOOLE_0:def 4;
verum
end; consider S being
sequence of
M such that A4:
for
n being
Element of
NAT holds
S1[
n,
S . n]
from FUNCT_2:sch 3(A2);
A6:
now for s being Real st 0 < s holds
ex k being Nat st
for m being Nat st k <= m holds
dist ((S . m),x0) < slet s be
Real;
( 0 < s implies ex k being Nat st
for m being Nat st k <= m holds
dist ((S . m),x0) < s )assume A7:
0 < s
;
ex k being Nat st
for m being Nat st k <= m holds
dist ((S . m),x0) < sconsider n being
Nat such that A8:
s " < n
by SEQ_4:3;
take k =
n;
for m being Nat st k <= m holds
dist ((S . m),x0) < slet m be
Nat;
( k <= m implies dist ((S . m),x0) < s )assume
k <= m
;
dist ((S . m),x0) < sthen
k + 1
<= m + 1
by XREAL_1:6;
then A9:
1
/ (m + 1) <= 1
/ (k + 1)
by XREAL_1:118;
(s ") + 0 < n + 1
by A8, XREAL_1:8;
then
1
/ (n + 1) < 1
/ (s ")
by A7, XREAL_1:76;
then
1
/ (m + 1) < s
by A9, XXREAL_0:2;
hence
dist (
(S . m),
x0)
< s
by A5, XXREAL_0:2;
verum end; then A10:
S is
convergent
;
then
lim S = x
by A6, TBSP_1:def 3;
hence
ex
S being
sequence of
M st
( ( for
n being
Nat holds
S . n in X ) &
S is
convergent &
lim S = x )
by A5, A10;
verum
end;
given S being sequence of M such that A11:
for n being Nat holds S . n in X
and
A12:
S is convergent
and
A13:
lim S = x
; x in Cl X
X c= Cl X
by PRE_TOPC:18;
then A14:
for n being Nat holds S . n in Cl X
by A11, TARSKI:def 3;
Cl (Cl X) = Cl X
;
hence
x in Cl X
by A12, A13, A14, PRE_TOPC:22, TOPMETR3:1; verum