let f, g be Function of G,G; ( ( for x being Element of G holds f . x = x * a ) & ( for x being Element of G holds g . x = x * a ) implies f = g )
assume that
A5:
for x being Element of G holds f . x = x * a
and
A6:
for x being Element of G holds g . x = x * a
; f = g
hence
f = g
; verum