let f, g be Function of G,G; ( ( for x being Element of G holds f . x = a * x ) & ( for x being Element of G holds g . x = a * x ) implies f = g )
assume that
A2:
for x being Element of G holds f . x = a * x
and
A3:
for x being Element of G holds g . x = a * x
; f = g
hence
f = g
; verum