let X, Y be non empty TopSpace; for X1, X2, X3 being non empty SubSpace of X
for f1 being Function of X1,Y
for f2 being Function of X2,Y
for f3 being Function of X3,Y st ( X1 misses X2 or f1 | (X1 meet X2) = f2 | (X1 meet X2) ) & ( X1 misses X3 or f1 | (X1 meet X3) = f3 | (X1 meet X3) ) & ( X2 misses X3 or f2 | (X2 meet X3) = f3 | (X2 meet X3) ) holds
(f1 union f2) union f3 = f1 union (f2 union f3)
let X1, X2, X3 be non empty SubSpace of X; for f1 being Function of X1,Y
for f2 being Function of X2,Y
for f3 being Function of X3,Y st ( X1 misses X2 or f1 | (X1 meet X2) = f2 | (X1 meet X2) ) & ( X1 misses X3 or f1 | (X1 meet X3) = f3 | (X1 meet X3) ) & ( X2 misses X3 or f2 | (X2 meet X3) = f3 | (X2 meet X3) ) holds
(f1 union f2) union f3 = f1 union (f2 union f3)
let f1 be Function of X1,Y; for f2 being Function of X2,Y
for f3 being Function of X3,Y st ( X1 misses X2 or f1 | (X1 meet X2) = f2 | (X1 meet X2) ) & ( X1 misses X3 or f1 | (X1 meet X3) = f3 | (X1 meet X3) ) & ( X2 misses X3 or f2 | (X2 meet X3) = f3 | (X2 meet X3) ) holds
(f1 union f2) union f3 = f1 union (f2 union f3)
let f2 be Function of X2,Y; for f3 being Function of X3,Y st ( X1 misses X2 or f1 | (X1 meet X2) = f2 | (X1 meet X2) ) & ( X1 misses X3 or f1 | (X1 meet X3) = f3 | (X1 meet X3) ) & ( X2 misses X3 or f2 | (X2 meet X3) = f3 | (X2 meet X3) ) holds
(f1 union f2) union f3 = f1 union (f2 union f3)
let f3 be Function of X3,Y; ( ( X1 misses X2 or f1 | (X1 meet X2) = f2 | (X1 meet X2) ) & ( X1 misses X3 or f1 | (X1 meet X3) = f3 | (X1 meet X3) ) & ( X2 misses X3 or f2 | (X2 meet X3) = f3 | (X2 meet X3) ) implies (f1 union f2) union f3 = f1 union (f2 union f3) )
assume that
A1:
( X1 misses X2 or f1 | (X1 meet X2) = f2 | (X1 meet X2) )
and
A2:
( X1 misses X3 or f1 | (X1 meet X3) = f3 | (X1 meet X3) )
and
A3:
( X2 misses X3 or f2 | (X2 meet X3) = f3 | (X2 meet X3) )
; (f1 union f2) union f3 = f1 union (f2 union f3)
set g = (f1 union f2) union f3;
A4:
(X1 union X2) union X3 = X1 union (X2 union X3)
by TSEP_1:21;
then reconsider f = (f1 union f2) union f3 as Function of (X1 union (X2 union X3)),Y ;
A5:
X1 union X2 is SubSpace of X1 union (X2 union X3)
by A4, TSEP_1:22;
A6:
now ( X1 union X2 meets X3 implies (f1 union f2) | ((X1 union X2) meet X3) = f3 | ((X1 union X2) meet X3) )assume A7:
X1 union X2 meets X3
;
(f1 union f2) | ((X1 union X2) meet X3) = f3 | ((X1 union X2) meet X3)now (f1 union f2) | ((X1 union X2) meet X3) = f3 | ((X1 union X2) meet X3)per cases
( ( X1 meets X3 & not X2 meets X3 ) or ( not X1 meets X3 & X2 meets X3 ) or ( X1 meets X3 & X2 meets X3 ) )
by A7, Th34;
suppose A14:
(
X1 meets X3 &
X2 meets X3 )
;
(f1 union f2) | ((X1 union X2) meet X3) = f3 | ((X1 union X2) meet X3)then
(
X1 meet X3 is
SubSpace of
X3 &
X2 meet X3 is
SubSpace of
X3 )
by TSEP_1:27;
then A15:
(X1 meet X3) union (X2 meet X3) is
SubSpace of
X3
by Th24;
A16:
X2 meet X3 is
SubSpace of
X2
by A14, TSEP_1:27;
A17:
X1 meet X3 is
SubSpace of
(X1 meet X3) union (X2 meet X3)
by TSEP_1:22;
then A18:
(f3 | ((X1 meet X3) union (X2 meet X3))) | (X1 meet X3) = f3 | (X1 meet X3)
by A15, Th72;
A19:
X1 meet X3 is
SubSpace of
X1
by A14, TSEP_1:27;
then A20:
(X1 meet X3) union (X2 meet X3) is
SubSpace of
X1 union X2
by A16, Th22;
then A21:
((f1 union f2) | ((X1 meet X3) union (X2 meet X3))) | (X1 meet X3) = (f1 union f2) | (X1 meet X3)
by A17, Th72;
X2 is
SubSpace of
X1 union X2
by TSEP_1:22;
then A22:
(f1 union f2) | (X2 meet X3) =
((f1 union f2) | X2) | (X2 meet X3)
by A16, Th72
.=
f2 | (X2 meet X3)
by A1, Def12
;
set v =
f3 | ((X1 meet X3) union (X2 meet X3));
A23:
X2 meet X3 is
SubSpace of
(X1 meet X3) union (X2 meet X3)
by TSEP_1:22;
then A24:
(f3 | ((X1 meet X3) union (X2 meet X3))) | (X2 meet X3) = f3 | (X2 meet X3)
by A15, Th72;
X1 is
SubSpace of
X1 union X2
by TSEP_1:22;
then A25:
(f1 union f2) | (X1 meet X3) =
((f1 union f2) | X1) | (X1 meet X3)
by A19, Th72
.=
f1 | (X1 meet X3)
by A1, Def12
;
A26:
((f1 union f2) | ((X1 meet X3) union (X2 meet X3))) | (X2 meet X3) = (f1 union f2) | (X2 meet X3)
by A20, A23, Th72;
(f1 union f2) | ((X1 union X2) meet X3) =
(f1 union f2) | ((X1 meet X3) union (X2 meet X3))
by A14, TSEP_1:32
.=
((f3 | ((X1 meet X3) union (X2 meet X3))) | (X1 meet X3)) union ((f3 | ((X1 meet X3) union (X2 meet X3))) | (X2 meet X3))
by A2, A3, A14, A25, A22, A21, A26, A18, A24, Th126
.=
f3 | ((X1 meet X3) union (X2 meet X3))
by Th126
;
hence
(f1 union f2) | ((X1 union X2) meet X3) = f3 | ((X1 union X2) meet X3)
by A14, TSEP_1:32;
verum end; end; end; hence
(f1 union f2) | ((X1 union X2) meet X3) = f3 | ((X1 union X2) meet X3)
;
verum end;
then
( X1 union X2 is SubSpace of (X1 union X2) union X3 & ((f1 union f2) union f3) | (X1 union X2) = f1 union f2 )
by Def12, TSEP_1:22;
then A27:
f | the carrier of (X1 union X2) = f1 union f2
by Def5;
A28:
X3 is SubSpace of X1 union (X2 union X3)
by A4, TSEP_1:22;
A29:
X2 union X3 is SubSpace of X1 union (X2 union X3)
by TSEP_1:22;
( X3 is SubSpace of (X1 union X2) union X3 & ((f1 union f2) union f3) | X3 = f3 )
by A6, Def12, TSEP_1:22;
then A30:
f | the carrier of X3 = f3
by Def5;
A31:
X1 union X2 is SubSpace of X1 union (X2 union X3)
by A4, TSEP_1:22;
X3 is SubSpace of X2 union X3
by TSEP_1:22;
then A32: (f | (X2 union X3)) | X3 =
f | X3
by A29, Th72
.=
f3
by A28, A30, Def5
;
X2 is SubSpace of X1 union X2
by TSEP_1:22;
then A33: f | X2 =
(f | (X1 union X2)) | X2
by A31, Th72
.=
(f1 union f2) | X2
by A5, A27, Def5
;
X2 is SubSpace of X2 union X3
by TSEP_1:22;
then (f | (X2 union X3)) | X2 =
f | X2
by A29, Th72
.=
f2
by A1, A33, Def12
;
then A34:
f | (X2 union X3) = f2 union f3
by A32, Th126;
X1 is SubSpace of X1 union X2
by TSEP_1:22;
then f | X1 =
(f | (X1 union X2)) | X1
by A31, Th72
.=
(f1 union f2) | X1
by A5, A27, Def5
;
then
f | X1 = f1
by A1, Def12;
hence
(f1 union f2) union f3 = f1 union (f2 union f3)
by A34, Th126; verum