let ADG be Uniquely_Two_Divisible_Group; ( ex a, b being Element of ADG st a <> b implies ( ex a, b being Element of (AV ADG) st a <> b & ( for a, b, c being Element of (AV ADG) st a,b // c,c holds
a = b ) & ( for a, b, c, d, p, q being Element of (AV ADG) st a,b // p,q & c,d // p,q holds
a,b // c,d ) & ( for a, b, c being Element of (AV ADG) ex d being Element of (AV ADG) st a,b // c,d ) & ( for a, b, c, a9, b9, c9 being Element of (AV ADG) st a,b // a9,b9 & a,c // a9,c9 holds
b,c // b9,c9 ) & ( for a, c being Element of (AV ADG) ex b being Element of (AV ADG) st a,b // b,c ) & ( for a, b, c, b9 being Element of (AV ADG) st a,b // b,c & a,b9 // b9,c holds
b = b9 ) & ( for a, b, c, d being Element of (AV ADG) st a,b // c,d holds
a,c // b,d ) ) )
set A = AV ADG;
assume
ex a, b being Element of ADG st a <> b
; ( ex a, b being Element of (AV ADG) st a <> b & ( for a, b, c being Element of (AV ADG) st a,b // c,c holds
a = b ) & ( for a, b, c, d, p, q being Element of (AV ADG) st a,b // p,q & c,d // p,q holds
a,b // c,d ) & ( for a, b, c being Element of (AV ADG) ex d being Element of (AV ADG) st a,b // c,d ) & ( for a, b, c, a9, b9, c9 being Element of (AV ADG) st a,b // a9,b9 & a,c // a9,c9 holds
b,c // b9,c9 ) & ( for a, c being Element of (AV ADG) ex b being Element of (AV ADG) st a,b // b,c ) & ( for a, b, c, b9 being Element of (AV ADG) st a,b // b,c & a,b9 // b9,c holds
b = b9 ) & ( for a, b, c, d being Element of (AV ADG) st a,b // c,d holds
a,c // b,d ) )
hence
ex a, b being Element of (AV ADG) st a <> b
; ( ( for a, b, c being Element of (AV ADG) st a,b // c,c holds
a = b ) & ( for a, b, c, d, p, q being Element of (AV ADG) st a,b // p,q & c,d // p,q holds
a,b // c,d ) & ( for a, b, c being Element of (AV ADG) ex d being Element of (AV ADG) st a,b // c,d ) & ( for a, b, c, a9, b9, c9 being Element of (AV ADG) st a,b // a9,b9 & a,c // a9,c9 holds
b,c // b9,c9 ) & ( for a, c being Element of (AV ADG) ex b being Element of (AV ADG) st a,b // b,c ) & ( for a, b, c, b9 being Element of (AV ADG) st a,b // b,c & a,b9 // b9,c holds
b = b9 ) & ( for a, b, c, d being Element of (AV ADG) st a,b // c,d holds
a,c // b,d ) )
A1:
for a9, b9, c9, d9 being Element of (AV ADG)
for a, b, c, d being Element of ADG st a = a9 & b = b9 & c = c9 & d = d9 holds
( a,b ==> c,d iff a9,b9 // c9,d9 )
by ANALOAF:def 2;
thus
for a, b, c being Element of (AV ADG) st a,b // c,c holds
a = b
( ( for a, b, c, d, p, q being Element of (AV ADG) st a,b // p,q & c,d // p,q holds
a,b // c,d ) & ( for a, b, c being Element of (AV ADG) ex d being Element of (AV ADG) st a,b // c,d ) & ( for a, b, c, a9, b9, c9 being Element of (AV ADG) st a,b // a9,b9 & a,c // a9,c9 holds
b,c // b9,c9 ) & ( for a, c being Element of (AV ADG) ex b being Element of (AV ADG) st a,b // b,c ) & ( for a, b, c, b9 being Element of (AV ADG) st a,b // b,c & a,b9 // b9,c holds
b = b9 ) & ( for a, b, c, d being Element of (AV ADG) st a,b // c,d holds
a,c // b,d ) )proof
let a,
b,
c be
Element of
(AV ADG);
( a,b // c,c implies a = b )
assume A2:
a,
b // c,
c
;
a = b
reconsider a9 =
a,
b9 =
b,
c9 =
c as
Element of
ADG ;
a9,
b9 ==> c9,
c9
by A1, A2;
hence
a = b
by Th8;
verum
end;
thus
for a, b, c, d, p, q being Element of (AV ADG) st a,b // p,q & c,d // p,q holds
a,b // c,d
( ( for a, b, c being Element of (AV ADG) ex d being Element of (AV ADG) st a,b // c,d ) & ( for a, b, c, a9, b9, c9 being Element of (AV ADG) st a,b // a9,b9 & a,c // a9,c9 holds
b,c // b9,c9 ) & ( for a, c being Element of (AV ADG) ex b being Element of (AV ADG) st a,b // b,c ) & ( for a, b, c, b9 being Element of (AV ADG) st a,b // b,c & a,b9 // b9,c holds
b = b9 ) & ( for a, b, c, d being Element of (AV ADG) st a,b // c,d holds
a,c // b,d ) )proof
let a,
b,
c,
d,
p,
q be
Element of
(AV ADG);
( a,b // p,q & c,d // p,q implies a,b // c,d )
reconsider a9 =
a,
b9 =
b,
c9 =
c,
d9 =
d,
p9 =
p,
q9 =
q as
Element of
ADG ;
assume
(
a,
b // p,
q &
c,
d // p,
q )
;
a,b // c,d
then
(
a9,
b9 ==> p9,
q9 &
c9,
d9 ==> p9,
q9 )
by A1;
then
a9,
b9 ==> c9,
d9
by Th9;
hence
a,
b // c,
d
by A1;
verum
end;
thus
for a, b, c being Element of (AV ADG) ex d being Element of (AV ADG) st a,b // c,d
( ( for a, b, c, a9, b9, c9 being Element of (AV ADG) st a,b // a9,b9 & a,c // a9,c9 holds
b,c // b9,c9 ) & ( for a, c being Element of (AV ADG) ex b being Element of (AV ADG) st a,b // b,c ) & ( for a, b, c, b9 being Element of (AV ADG) st a,b // b,c & a,b9 // b9,c holds
b = b9 ) & ( for a, b, c, d being Element of (AV ADG) st a,b // c,d holds
a,c // b,d ) )proof
let a,
b,
c be
Element of
(AV ADG);
ex d being Element of (AV ADG) st a,b // c,d
reconsider a9 =
a,
b9 =
b,
c9 =
c as
Element of
ADG ;
consider d9 being
Element of
ADG such that A3:
a9,
b9 ==> c9,
d9
by Th10;
reconsider d =
d9 as
Element of
(AV ADG) ;
take
d
;
a,b // c,d
thus
a,
b // c,
d
by A1, A3;
verum
end;
thus
for a, b, c, a9, b9, c9 being Element of (AV ADG) st a,b // a9,b9 & a,c // a9,c9 holds
b,c // b9,c9
( ( for a, c being Element of (AV ADG) ex b being Element of (AV ADG) st a,b // b,c ) & ( for a, b, c, b9 being Element of (AV ADG) st a,b // b,c & a,b9 // b9,c holds
b = b9 ) & ( for a, b, c, d being Element of (AV ADG) st a,b // c,d holds
a,c // b,d ) )proof
let a,
b,
c,
a9,
b9,
c9 be
Element of
(AV ADG);
( a,b // a9,b9 & a,c // a9,c9 implies b,c // b9,c9 )
reconsider p =
a,
q =
b,
r =
c,
p9 =
a9,
q9 =
b9,
r9 =
c9 as
Element of
ADG ;
assume
(
a,
b // a9,
b9 &
a,
c // a9,
c9 )
;
b,c // b9,c9
then
(
p,
q ==> p9,
q9 &
p,
r ==> p9,
r9 )
by A1;
then
q,
r ==> q9,
r9
by Th11;
hence
b,
c // b9,
c9
by A1;
verum
end;
thus
for a, c being Element of (AV ADG) ex b being Element of (AV ADG) st a,b // b,c
( ( for a, b, c, b9 being Element of (AV ADG) st a,b // b,c & a,b9 // b9,c holds
b = b9 ) & ( for a, b, c, d being Element of (AV ADG) st a,b // c,d holds
a,c // b,d ) )proof
let a,
c be
Element of
(AV ADG);
ex b being Element of (AV ADG) st a,b // b,c
reconsider a9 =
a,
c9 =
c as
Element of
ADG ;
consider b9 being
Element of
ADG such that A4:
a9,
b9 ==> b9,
c9
by Th12;
reconsider b =
b9 as
Element of
(AV ADG) ;
take
b
;
a,b // b,c
thus
a,
b // b,
c
by A1, A4;
verum
end;
thus
for a, b, c, b9 being Element of (AV ADG) st a,b // b,c & a,b9 // b9,c holds
b = b9
for a, b, c, d being Element of (AV ADG) st a,b // c,d holds
a,c // b,dproof
let a,
b,
c,
b9 be
Element of
(AV ADG);
( a,b // b,c & a,b9 // b9,c implies b = b9 )
reconsider a9 =
a,
p =
b,
c9 =
c,
p9 =
b9 as
Element of
ADG ;
assume
(
a,
b // b,
c &
a,
b9 // b9,
c )
;
b = b9
then
(
a9,
p ==> p,
c9 &
a9,
p9 ==> p9,
c9 )
by A1;
hence
b = b9
by Th13;
verum
end;
thus
for a, b, c, d being Element of (AV ADG) st a,b // c,d holds
a,c // b,d
verumproof
let a,
b,
c,
d be
Element of
(AV ADG);
( a,b // c,d implies a,c // b,d )
reconsider a9 =
a,
b9 =
b,
c9 =
c,
d9 =
d as
Element of
ADG ;
assume
a,
b // c,
d
;
a,c // b,d
then
a9,
b9 ==> c9,
d9
by A1;
then
a9,
c9 ==> b9,
d9
by Th14;
hence
a,
c // b,
d
by A1;
verum
end;