let ADG be Uniquely_Two_Divisible_Group; for a, b, c, d being Element of ADG st a,b ==> c,d holds
a,c ==> b,d
let a, b, c, d be Element of ADG; ( a,b ==> c,d implies a,c ==> b,d )
assume
a,b ==> c,d
; a,c ==> b,d
then
a + d = b + c
by Th5;
hence
a,c ==> b,d
by Th5; verum