let x, y be Surreal; for X1, X2, Y1, Y2 being set st X1 <==> X2 & Y1 <==> Y2 & x = [X1,Y1] & y = [X2,Y2] holds
x == y
let X1, X2, Y1, Y2 be set ; ( X1 <==> X2 & Y1 <==> Y2 & x = [X1,Y1] & y = [X2,Y2] implies x == y )
assume A1:
( X1 <==> X2 & Y1 <==> Y2 & x = [X1,Y1] & y = [X2,Y2] )
; x == y
hence
x == y
by SURREAL0:44, A1, A2, A3, A4; verum