let n be Nat; :: thesis: for i being Integer st - n < i & i < n holds
( uInt . (- n) < uInt . i & uInt . i < uInt . n )

let i be Integer; :: thesis: ( - n < i & i < n implies ( uInt . (- n) < uInt . i & uInt . i < uInt . n ) )
assume A1: ( - n < i & i < n ) ; :: thesis: ( uInt . (- n) < uInt . i & uInt . i < uInt . n )
i in INT by INT_1:def 2;
then consider k being Nat such that
A2: ( i = k or i = - k ) by INT_1:def 1;
Segm k c= Segm n by A2, A1, XREAL_1:24, NAT_1:39;
then A3: Day k c= Day n by SURREAL0:35;
A4: ( born_eq (uInt . n) = n & n = born_eq (uInt . (- n)) ) by Th5;
born_eq (uInt . i) = k by A2, Th5;
then A5: ( not uInt . n == uInt . i & not uInt . i == uInt . (- n) ) by A4, SURREALO:50, A2, A1;
born (uInt . i) = k by A2, Th4;
then uInt . i in Day k by SURREAL0:def 18;
hence ( uInt . (- n) < uInt . i & uInt . i < uInt . n ) by Th2, A5, A3; :: thesis: verum