i in INT
by INT_1:def 2;
then consider o being Nat such that
A1:
( i = o or i = - o )
by INT_1:def 1;
per cases
( i = o or i = - o )
by A1;
suppose A2:
i = o
;
uInt . i is uniq-surreal defpred S1[
Nat]
means uInt . i is
uniq-surreal ;
A3:
S1[
0 ]
by Def1;
A4:
for
n being
Nat st
S1[
n] holds
S1[
n + 1]
proof
let n be
Nat;
( S1[n] implies S1[n + 1] )
assume
S1[
n]
;
S1[n + 1]
then reconsider sn =
uInt . n as
uSurreal ;
set n1 =
n + 1;
set x =
uInt . (n + 1);
A5:
uInt . (n + 1) in Day (born (uInt . (n + 1)))
by SURREAL0:def 18;
A6:
(
born_eq (uInt . (n + 1)) = n + 1 &
n + 1
= born (uInt . (n + 1)) )
by Th5, Th4;
then A7:
uInt . (n + 1) in born_eq_set (uInt . (n + 1))
by A5, SURREALO:def 6;
A8:
uInt . (n + 1) = [{sn},{}]
by Def1;
then A9:
(L_ (uInt . (n + 1))) \/ (R_ (uInt . (n + 1))) is
uniq-surreal-membered
;
for
z being
Surreal st
z in born_eq_set (uInt . (n + 1)) &
(L_ z) \/ (R_ z) is
uniq-surreal-membered &
uInt . (n + 1) <> z holds
(card (L_ (uInt . (n + 1)))) (+) (card (R_ (uInt . (n + 1)))) in (card (L_ z)) (+) (card (R_ z))
proof
let z be
Surreal;
( z in born_eq_set (uInt . (n + 1)) & (L_ z) \/ (R_ z) is uniq-surreal-membered & uInt . (n + 1) <> z implies (card (L_ (uInt . (n + 1)))) (+) (card (R_ (uInt . (n + 1)))) in (card (L_ z)) (+) (card (R_ z)) )
assume that A10:
(
z in born_eq_set (uInt . (n + 1)) &
(L_ z) \/ (R_ z) is
uniq-surreal-membered )
and A11:
uInt . (n + 1) <> z
and A12:
not
(card (L_ (uInt . (n + 1)))) (+) (card (R_ (uInt . (n + 1)))) in (card (L_ z)) (+) (card (R_ z))
;
contradiction
A13:
z == uInt . (n + 1)
by A10, SURREALO:def 6;
A14:
(card (L_ (uInt . (n + 1)))) (+) (card (R_ (uInt . (n + 1)))) = 1
by A8, SURREALO:47;
then
(card (L_ z)) (+) (card (R_ z)) c= 1
by A12, ORDINAL1:16;
then reconsider cz =
(card (L_ z)) (+) (card (R_ z)) as
Nat ;
cz <> 0
then A16:
1
<= cz
by NAT_1:14;
Segm cz c= Segm 1
by A14, A12, ORDINAL1:16;
then
cz <= 1
by NAT_1:39;
then consider r being
Surreal such that A17:
(
z = [{},{r}] or
z = [{r},{}] )
by SURREALO:47, A16, XXREAL_0:1;
A18:
r in (L_ z) \/ (R_ z)
by A17, TARSKI:def 1;
then reconsider r =
r as
uSurreal by A10;
A19:
(
born z = born_eq z &
born_eq z = born_eq (uInt . (n + 1)) )
by A10, SURREALO:35;
A20:
born r in n + 1
by A19, A6, SURREALO:1, A18;
then A21:
(
r in Day (born r) &
Day (born r) c= Day (n + 1) )
by SURREAL0:35, SURREAL0:def 18, ORDINAL1:def 2;
per cases
( z = [{},{r}] or z = [{r},{}] )
by A17;
suppose A24:
z = [{r},{}]
;
contradictionthen A25:
not
r == sn
by A11, A8, SURREALO:50;
n + 1
= Segm (n + 1)
;
then
born r in succ (Segm n)
by A20, NAT_1:38;
then A26:
(
r in Day (born r) &
Day (born r) c= Day n )
by ORDINAL1:22, SURREAL0:35, SURREAL0:def 18;
(
L_ z << {sn} &
{z} << R_ sn )
by Th7, A24, SURREALO:21, A26, Th2, A25;
then
not
L_ (uInt . (n + 1)) << {z}
by SURREAL0:43, A8, SURREALO:21;
hence
contradiction
by A13, SURREAL0:43;
verum end; end;
end;
hence
S1[
n + 1]
by A7, A9, SURREALO:49;
verum
end;
for
n being
Nat holds
S1[
n]
from NAT_1:sch 2(A3, A4);
hence
uInt . i is
uniq-surreal
by A2;
verum end; suppose A27:
i = - o
;
uInt . i is uniq-surreal defpred S1[
Nat]
means uInt . (- i) is
uniq-surreal ;
A28:
S1[
0 ]
by Def1;
A29:
for
n being
Nat st
S1[
n] holds
S1[
n + 1]
proof
let n be
Nat;
( S1[n] implies S1[n + 1] )
assume
S1[
n]
;
S1[n + 1]
then reconsider sn =
uInt . (- n) as
uSurreal ;
set n1 =
n + 1;
set x =
uInt . (- (n + 1));
A30:
uInt . (- (n + 1)) in Day (born (uInt . (- (n + 1))))
by SURREAL0:def 18;
A31:
(
born_eq (uInt . (- (n + 1))) = n + 1 &
n + 1
= born (uInt . (- (n + 1))) )
by Th5, Th4;
then A32:
uInt . (- (n + 1)) in born_eq_set (uInt . (- (n + 1)))
by A30, SURREALO:def 6;
A33:
uInt . (- (n + 1)) = [{},{sn}]
by Def1;
then A34:
(L_ (uInt . (- (n + 1)))) \/ (R_ (uInt . (- (n + 1)))) is
uniq-surreal-membered
;
for
z being
Surreal st
z in born_eq_set (uInt . (- (n + 1))) &
(L_ z) \/ (R_ z) is
uniq-surreal-membered &
uInt . (- (n + 1)) <> z holds
(card (L_ (uInt . (- (n + 1))))) (+) (card (R_ (uInt . (- (n + 1))))) in (card (L_ z)) (+) (card (R_ z))
proof
let z be
Surreal;
( z in born_eq_set (uInt . (- (n + 1))) & (L_ z) \/ (R_ z) is uniq-surreal-membered & uInt . (- (n + 1)) <> z implies (card (L_ (uInt . (- (n + 1))))) (+) (card (R_ (uInt . (- (n + 1))))) in (card (L_ z)) (+) (card (R_ z)) )
assume that A35:
(
z in born_eq_set (uInt . (- (n + 1))) &
(L_ z) \/ (R_ z) is
uniq-surreal-membered )
and A36:
uInt . (- (n + 1)) <> z
and A37:
not
(card (L_ (uInt . (- (n + 1))))) (+) (card (R_ (uInt . (- (n + 1))))) in (card (L_ z)) (+) (card (R_ z))
;
contradiction
A38:
z == uInt . (- (n + 1))
by A35, SURREALO:def 6;
A39:
(card (L_ (uInt . (- (n + 1))))) (+) (card (R_ (uInt . (- (n + 1))))) = 1
by A33, SURREALO:47;
then
(card (L_ z)) (+) (card (R_ z)) c= 1
by A37, ORDINAL1:16;
then reconsider cz =
(card (L_ z)) (+) (card (R_ z)) as
Nat ;
cz <> 0
then A41:
1
<= cz
by NAT_1:14;
Segm cz c= Segm 1
by A39, A37, ORDINAL1:16;
then
cz <= 1
by NAT_1:39;
then consider r being
Surreal such that A42:
(
z = [{},{r}] or
z = [{r},{}] )
by SURREALO:47, A41, XXREAL_0:1;
A43:
r in (L_ z) \/ (R_ z)
by A42, TARSKI:def 1;
then reconsider r =
r as
uSurreal by A35;
A44:
(
born z = born_eq z &
born_eq z = born_eq (uInt . (- (n + 1))) )
by A35, SURREALO:35;
A45:
born r in n + 1
by A44, A31, SURREALO:1, A43;
then A46:
(
r in Day (born r) &
Day (born r) c= Day (n + 1) )
by SURREAL0:35, SURREAL0:def 18, ORDINAL1:def 2;
per cases
( z = [{r},{}] or z = [{},{r}] )
by A42;
suppose A49:
z = [{},{r}]
;
contradictionthen A50:
not
r == sn
by A36, A33, SURREALO:50;
n + 1
= Segm (n + 1)
;
then
born r in succ (Segm n)
by A45, NAT_1:38;
then A51:
(
r in Day (born r) &
Day (born r) c= Day n )
by ORDINAL1:22, SURREAL0:35, SURREAL0:def 18;
(
R_ z >> {sn} &
{z} >> L_ sn )
by Th7, A49, A51, Th2, A50, SURREALO:21;
then
not
R_ (uInt . (- (n + 1))) >> {z}
by SURREAL0:43, A33, SURREALO:21;
hence
contradiction
by A38, SURREAL0:43;
verum end; end;
end;
hence
S1[
n + 1]
by A32, A34, SURREALO:49;
verum
end;
for
n being
Nat holds
S1[
n]
from NAT_1:sch 2(A28, A29);
hence
uInt . i is
uniq-surreal
by A27;
verum end; end;