let X1, X2, Y1, Y2 be surreal-membered set ; ( X2 <=_ X1 & Y2 <=_ Y1 & [X1,Y1] is surreal implies [X2,Y2] is surreal )
assume A1:
( X2 <=_ X1 & Y2 <=_ Y1 & [X1,Y1] is surreal )
; [X2,Y2] is surreal
A2:
X2 << Y2
proof
let l,
r be
Surreal;
SURREAL0:def 20 ( not l in X2 or not r in Y2 or not r <= l )
assume A3:
(
l in X2 &
r in Y2 )
;
not r <= l
consider l1,
l2 being
Surreal such that A4:
(
l1 in X1 &
l2 in X1 &
l1 <= l &
l <= l2 )
by A3, A1;
consider r1,
r2 being
Surreal such that A5:
(
r1 in Y1 &
r2 in Y1 &
r1 <= r &
r <= r2 )
by A3, A1;
(
X1 = L_ [X1,Y1] &
L_ [X1,Y1] << R_ [X1,Y1] &
R_ [X1,Y1] = Y1 )
by A1, SURREAL0:45;
then
l < r1
by A4, A5, SURREALO:4;
hence
not
r <= l
by A5, SURREALO:4;
verum
end;
consider M being Ordinal such that
A6:
for o being object st o in X2 \/ Y2 holds
ex A being Ordinal st
( A in M & o in Day A )
by SURREAL0:47;
[X2,Y2] in Day M
by A6, A2, SURREAL0:46;
hence
[X2,Y2] is surreal
; verum