let x be Surreal; :: thesis: ( x is positive implies x " = [(({0_No} \/ (divset ((R_ x),||.x.||,(L_ (x "))))) \/ (divset ((L_ x),||.x.||,(R_ (x "))))),((divset ((L_ x),||.x.||,(L_ (x ")))) \/ (divset ((R_ x),||.x.||,(R_ (x ")))))] )
set Nx = ||.x.||;
set Inv = No_inverses_on ||.x.||;
assume A1: x is positive ; :: thesis: x " = [(({0_No} \/ (divset ((R_ x),||.x.||,(L_ (x "))))) \/ (divset ((L_ x),||.x.||,(R_ (x "))))),((divset ((L_ x),||.x.||,(L_ (x ")))) \/ (divset ((R_ x),||.x.||,(R_ (x ")))))]
then not x == 0_No ;
then A2: x " = inv x by A1, Def14;
set UL = Union (divL (||.x.||,(No_inverses_on ||.x.||)));
set UR = Union (divR (||.x.||,(No_inverses_on ||.x.||)));
A3: inv x = [(Union (divL (||.x.||,(No_inverses_on ||.x.||)))),(Union (divR (||.x.||,(No_inverses_on ||.x.||))))] by A1, Th26;
then Union (divL (||.x.||,(No_inverses_on ||.x.||))) c= (L_ (x ")) \/ (R_ (x ")) by A2, XBOOLE_1:7;
then A4: ( divset ((Union (divL (||.x.||,(No_inverses_on ||.x.||)))),||.x.||,(R_ ||.x.||),(No_inverses_on ||.x.||)) = divset ((R_ x),||.x.||,(Union (divL (||.x.||,(No_inverses_on ||.x.||))))) & divset ((Union (divL (||.x.||,(No_inverses_on ||.x.||)))),||.x.||,(L_ ||.x.||),(No_inverses_on ||.x.||)) = divset ((L_ x),||.x.||,(Union (divL (||.x.||,(No_inverses_on ||.x.||))))) ) by A1, A2, A3, Th34;
Union (divR (||.x.||,(No_inverses_on ||.x.||))) c= (L_ (x ")) \/ (R_ (x ")) by A2, A3, XBOOLE_1:7;
then A5: ( divset ((Union (divR (||.x.||,(No_inverses_on ||.x.||)))),||.x.||,(L_ ||.x.||),(No_inverses_on ||.x.||)) = divset ((L_ x),||.x.||,(Union (divR (||.x.||,(No_inverses_on ||.x.||))))) & divset ((Union (divR (||.x.||,(No_inverses_on ||.x.||)))),||.x.||,(R_ ||.x.||),(No_inverses_on ||.x.||)) = divset ((R_ x),||.x.||,(Union (divR (||.x.||,(No_inverses_on ||.x.||))))) ) by A1, A2, A3, Th34;
Union (divL (||.x.||,(No_inverses_on ||.x.||))) = ({0_No} \/ (divset ((Union (divL (||.x.||,(No_inverses_on ||.x.||)))),||.x.||,(R_ ||.x.||),(No_inverses_on ||.x.||)))) \/ (divset ((Union (divR (||.x.||,(No_inverses_on ||.x.||)))),||.x.||,(L_ ||.x.||),(No_inverses_on ||.x.||))) by Th12;
hence x " = [(({0_No} \/ (divset ((R_ x),||.x.||,(L_ (x "))))) \/ (divset ((L_ x),||.x.||,(R_ (x "))))),((divset ((L_ x),||.x.||,(L_ (x ")))) \/ (divset ((R_ x),||.x.||,(R_ (x ")))))] by A4, A5, A3, A2, Th13; :: thesis: verum