consider O being Ordinal such that
A1:
x in Day O
by Def14;
take b = born ((No_Ord O),x); ( x in Day b & ( for O being Ordinal st x in Day O holds
b c= O ) )
A2:
b c= O
by A1, Def8;
A3:
x in Day ((No_Ord O),b)
by Def8, A1;
hence
x in Day b
by A2, Th36; for O being Ordinal st x in Day O holds
b c= O
let A be Ordinal; ( x in Day A implies b c= A )
assume A4:
x in Day A
; b c= A
(No_Ord b) /\ [:(BeforeGames b),(BeforeGames b):] = (No_Ord O) /\ [:(BeforeGames b),(BeforeGames b):]
by A2, Th31;
then A5:
b = born ((No_Ord b),x)
by A3, Th11;
A6:
born ((No_Ord A),x) c= A
by A4, Def8;
assume A7:
not b c= A
; contradiction
then
(No_Ord b) /\ [:(BeforeGames A),(BeforeGames A):] = (No_Ord A) /\ [:(BeforeGames A),(BeforeGames A):]
by Th31;
hence
contradiction
by A5, A7, A6, Th11, A4; verum