set D = cobool X;
for x, y being set st x in cobool X & y in cobool X holds
x /\ y in cobool X
proof
let x, y be set ; :: thesis: ( x in cobool X & y in cobool X implies x /\ y in cobool X )
assume ( x in cobool X & y in cobool X ) ; :: thesis: x /\ y in cobool X
per cases then ( x = {} or ( x = X & y = X ) or ( x = X & y = {} ) ) by TARSKI:def 2;
end;
end;
hence cobool X is cap-closed ; :: thesis: verum