let n be Element of NAT ; for Z being open Subset of REAL st Z c= dom ((#Z n) * arctan) & Z c= ].(- 1),1.[ holds
( (#Z n) * arctan is_differentiable_on Z & ( for x being Real st x in Z holds
(((#Z n) * arctan) `| Z) . x = (n * ((arctan . x) #Z (n - 1))) / (1 + (x ^2)) ) )
let Z be open Subset of REAL; ( Z c= dom ((#Z n) * arctan) & Z c= ].(- 1),1.[ implies ( (#Z n) * arctan is_differentiable_on Z & ( for x being Real st x in Z holds
(((#Z n) * arctan) `| Z) . x = (n * ((arctan . x) #Z (n - 1))) / (1 + (x ^2)) ) ) )
assume that
A1:
Z c= dom ((#Z n) * arctan)
and
A2:
Z c= ].(- 1),1.[
; ( (#Z n) * arctan is_differentiable_on Z & ( for x being Real st x in Z holds
(((#Z n) * arctan) `| Z) . x = (n * ((arctan . x) #Z (n - 1))) / (1 + (x ^2)) ) )
A3:
for x being Real st x in Z holds
(#Z n) * arctan is_differentiable_in x
then A5:
(#Z n) * arctan is_differentiable_on Z
by A1, FDIFF_1:9;
for x being Real st x in Z holds
(((#Z n) * arctan) `| Z) . x = (n * ((arctan . x) #Z (n - 1))) / (1 + (x ^2))
proof
let x be
Real;
( x in Z implies (((#Z n) * arctan) `| Z) . x = (n * ((arctan . x) #Z (n - 1))) / (1 + (x ^2)) )
assume A6:
x in Z
;
(((#Z n) * arctan) `| Z) . x = (n * ((arctan . x) #Z (n - 1))) / (1 + (x ^2))
then A7:
- 1
< x
by A2, XXREAL_1:4;
arctan is_differentiable_on Z
by A2, Th81;
then A8:
arctan is_differentiable_in x
by A6, FDIFF_1:9;
A9:
x < 1
by A2, A6, XXREAL_1:4;
(((#Z n) * arctan) `| Z) . x =
diff (
((#Z n) * arctan),
x)
by A5, A6, FDIFF_1:def 7
.=
(n * ((arctan . x) #Z (n - 1))) * (diff (arctan,x))
by A8, TAYLOR_1:3
.=
(n * ((arctan . x) #Z (n - 1))) * (1 / (1 + (x ^2)))
by A7, A9, Th75
.=
(n * ((arctan . x) #Z (n - 1))) / (1 + (x ^2))
;
hence
(((#Z n) * arctan) `| Z) . x = (n * ((arctan . x) #Z (n - 1))) / (1 + (x ^2))
;
verum
end;
hence
( (#Z n) * arctan is_differentiable_on Z & ( for x being Real st x in Z holds
(((#Z n) * arctan) `| Z) . x = (n * ((arctan . x) #Z (n - 1))) / (1 + (x ^2)) ) )
by A1, A3, FDIFF_1:9; verum