let f be Function; for X, Y being set st f | X is one-to-one & Y c= X holds
f | Y is one-to-one
let X, Y be set ; ( f | X is one-to-one & Y c= X implies f | Y is one-to-one )
assume that
A1:
f | X is one-to-one
and
A2:
Y c= X
; f | Y is one-to-one
let x, y be object ; FUNCT_1:def 4 ( not x in dom (f | Y) or not y in dom (f | Y) or not (f | Y) . x = (f | Y) . y or x = y )
A3:
dom (f | Y) = (dom f) /\ Y
by RELAT_1:61;
assume A4:
x in dom (f | Y)
; ( not y in dom (f | Y) or not (f | Y) . x = (f | Y) . y or x = y )
then A5:
x in Y
by A3, XBOOLE_0:def 4;
x in dom f
by A3, A4, XBOOLE_0:def 4;
then
x in (dom f) /\ X
by A2, A5, XBOOLE_0:def 4;
then A6:
x in dom (f | X)
by RELAT_1:61;
assume A7:
y in dom (f | Y)
; ( not (f | Y) . x = (f | Y) . y or x = y )
then A8:
y in Y
by A3, XBOOLE_0:def 4;
y in dom f
by A3, A7, XBOOLE_0:def 4;
then
y in (dom f) /\ X
by A2, A8, XBOOLE_0:def 4;
then A9:
y in dom (f | X)
by RELAT_1:61;
assume A10:
(f | Y) . x = (f | Y) . y
; x = y
(f | X) . x =
f . x
by A2, A5, FUNCT_1:49
.=
(f | Y) . x
by A5, FUNCT_1:49
.=
f . y
by A8, A10, FUNCT_1:49
.=
(f | X) . y
by A2, A8, FUNCT_1:49
;
hence
x = y
by A1, A6, A9; verum