let L be non empty satisfying_Sh_1 ShefferStr ; :: thesis: for x, y, z being Element of L holds (x | (y | y)) | (x | (z | ((y | y) | x))) = (x | (z | y)) | (x | (z | y))
let x, y, z be Element of L; :: thesis: (x | (y | y)) | (x | (z | ((y | y) | x))) = (x | (z | y)) | (x | (z | y))
x | (z | ((y | y) | x)) = x | (z | y) by Th62;
hence (x | (y | y)) | (x | (z | ((y | y) | x))) = (x | (z | y)) | (x | (z | y)) by Th45; :: thesis: verum