per cases
( ( not x in A & ( for n being Nat holds not for k being Nat holds x in A1 .(n + k) ) ) or ( x in A & ex n being Nat st for k being Nat holds x in A1 .(n + k) ) )
byA3, KURATO_0:4;
suppose A4:
( not x in A & ( for n being Nat holds not for k being Nat holds x in A1 .(n + k) ) )
; :: thesis: contradiction
then
not for k1 being Nat holds x in A1 .(n1 + k1)
; hence
contradiction
byA2, A4; :: thesis: verum
then consider n2 being Nat such that A6:
for k being Nat holds x in A1 .(n2 + k)
;
x in A1 .(n2 + n1)byA6; hence
contradiction
byA2, A5; :: thesis: verum