then consider n1 being Nat such that A6:
for k being Nat holds not x in A1 .(n1 + k)byKURATO_0:5;
ex k2 being Nat st ( x in A1 .(n1 + k2) & not x in A2 .(n1 + k2) )
byA3; hence
contradiction
byA6; :: thesis: verum
then consider n2 being Nat such that A7:
for k being Nat holds x in A2 .(n2 + k)byKURATO_0:4;
ex k3 being Nat st ( x in A1 .(n2 + k3) & not x in A2 .(n2 + k3) )
byA3; hence
contradiction
byA7; :: thesis: verum