let s be Real_Sequence; :: thesis: ( ( for n being Nat holds s . n = 1 / (((n * (n + 1)) * (n + 2)) * (n + 3)) ) implies for n being Nat holds (Partial_Sums s) . n = (1 / 18) - (1 / (((3 * (n + 1)) * (n + 2)) * (n + 3))) )
defpred S1[ Nat] means (Partial_Sums s) . $1 = (1 / 18) - (1 / (((3 * ($1 + 1)) * ($1 + 2)) * ($1 + 3)));
assume A1: for n being Nat holds s . n = 1 / (((n * (n + 1)) * (n + 2)) * (n + 3)) ; :: thesis: for n being Nat holds (Partial_Sums s) . n = (1 / 18) - (1 / (((3 * (n + 1)) * (n + 2)) * (n + 3)))
A2: for n being Nat st S1[n] holds
S1[n + 1]
proof
let n be Nat; :: thesis: ( S1[n] implies S1[n + 1] )
assume (Partial_Sums s) . n = (1 / 18) - (1 / (((3 * (n + 1)) * (n + 2)) * (n + 3))) ; :: thesis: S1[n + 1]
then (Partial_Sums s) . (n + 1) = ((1 / 18) - (1 / (((3 * (n + 1)) * (n + 2)) * (n + 3)))) + (s . (n + 1)) by SERIES_1:def 1
.= ((1 / 18) - (1 / (((3 * (n + 1)) * (n + 2)) * (n + 3)))) + (1 / ((((n + 1) * ((n + 1) + 1)) * ((n + 1) + 2)) * ((n + 1) + 3))) by A1
.= (1 / 18) - ((1 / (((3 * (n + 1)) * (n + 2)) * (n + 3))) - (1 / ((((n + 1) * (n + 2)) * (n + 3)) * (n + 4))))
.= (1 / 18) - ((1 / (((3 * (n + 1)) * (n + 2)) * (n + 3))) - ((1 * 3) / (((((n + 1) * (n + 2)) * (n + 3)) * (n + 4)) * 3))) by XCMPLX_1:91
.= (1 / 18) - ((1 / (((3 * (n + 2)) * (n + 3)) * (n + 1))) - ((1 * 3) / (((3 * (n + 2)) * (n + 3)) * ((n + 1) * (n + 4)))))
.= (1 / 18) - ((1 / (((3 * (n + 2)) * (n + 3)) * (n + 1))) - ((1 / ((3 * (n + 2)) * (n + 3))) * (3 / ((n + 1) * (n + 4))))) by XCMPLX_1:76
.= (1 / 18) - (((1 / ((3 * (n + 2)) * (n + 3))) * (1 / (n + 1))) - ((1 / ((3 * (n + 2)) * (n + 3))) * (3 / ((n + 1) * (n + 4))))) by XCMPLX_1:102
.= (1 / 18) - ((1 / ((3 * (n + 2)) * (n + 3))) * ((1 / (n + 1)) - (3 / ((n + 1) * (n + 4)))))
.= (1 / 18) - ((1 / ((3 * (n + 2)) * (n + 3))) * (1 / (n + 4))) by Lm9
.= (1 / 18) - (1 / (((3 * ((n + 1) + 1)) * ((n + 1) + 2)) * ((n + 1) + 3))) by XCMPLX_1:102 ;
hence S1[n + 1] ; :: thesis: verum
end;
(Partial_Sums s) . 0 = s . 0 by SERIES_1:def 1
.= 1 / (((0 * (0 + 1)) * (0 + 2)) * (0 + 3)) by A1
.= (1 / 18) - (1 / (((3 * (0 + 1)) * (0 + 2)) * (0 + 3))) by XCMPLX_1:49 ;
then A3: S1[ 0 ] ;
for n being Nat holds S1[n] from NAT_1:sch 2(A3, A2);
hence for n being Nat holds (Partial_Sums s) . n = (1 / 18) - (1 / (((3 * (n + 1)) * (n + 2)) * (n + 3))) ; :: thesis: verum